A*B*A, where * represents XOR, is equal to:
B
The question asks us to simplify the expression A * B * A, where the asterisk (*) represents the XOR operation. The XOR (Exclusive OR) operation is a fundamental concept in digital logic and Boolean algebra. It is a binary operation that outputs true (1) only when inputs differ (one is true, the other is false) and outputs false (0) when inputs are the same (both true or both false).
The symbol commonly used for XOR is $\oplus$. So, the expression can be written as A $\oplus$ B $\oplus$ A.
To simplify this expression, we need to use the properties of the XOR operation. The most relevant properties for this problem are:
Let's simplify the expression A $\oplus$ B $\oplus$ A using these properties:
So, the simplified expression is B.
Let's quickly verify with an example using binary values (A=1, B=0):
A $\oplus$ B $\oplus$ A = 1 $\oplus$ 0 $\oplus$ 1
= (1 $\oplus$ 0) $\oplus$ 1 (Using Associative Property)
= 1 $\oplus$ 1 (Since 1 $\oplus$ 0 = 1)
= 0 (Since 1 $\oplus$ 1 = 0)
Wait, this example does not yield B (which is 0). Let's re-examine the steps and example.
The grouping (A $\oplus$ A) $\oplus$ B is correct due to associativity and commutativity. Let's retry the example carefully with the correct grouping:
A $\oplus$ B $\oplus$ A = (A $\oplus$ A) $\oplus$ B
Let A = 1, B = 0:
(1 $\oplus$ 1) $\oplus$ 0
= 0 $\oplus$ 0 (Since 1 $\oplus$ 1 = 0)
= 0 (Since 0 $\oplus$ 0 = 0)
In this example, B was 0, and the result is 0. So, the result B holds for this example.
Let A = 1, B = 1:
(1 $\oplus$ 1) $\oplus$ 1
= 0 $\oplus$ 1 (Since 1 $\oplus$ 1 = 0)
= 1 (Since 0 $\oplus$ 1 = 1)
In this example, B was 1, and the result is 1. So, the result B holds for this example too.
Let A = 0, B = 1:
(0 $\oplus$ 0) $\oplus$ 1
= 0 $\oplus$ 1 (Since 0 $\oplus$ 0 = 0)
= 1 (Since 0 $\oplus$ 1 = 1)
In this example, B was 1, and the result is 1. The result B holds.
Let A = 0, B = 0:
(0 $\oplus$ 0) $\oplus$ 0
= 0 $\oplus$ 0 (Since 0 $\oplus$ 0 = 0)
= 0 (Since 0 $\oplus$ 0 = 0)
In this example, B was 0, and the result is 0. The result B holds.
The step-by-step simplification using the properties of XOR is robust and confirmed by examples.
The simplified expression is B. Let's look at the provided options:
Our result, B, matches the first option.
| Property | Description | Expression |
|---|---|---|
| Commutative | Order doesn't matter | A $\oplus$ B = B $\oplus$ A |
| Associative | Grouping doesn't matter | (A $\oplus$ B) $\oplus$ C = A $\oplus$ (B $\oplus$ C) |
| Inverse | XOR with self | A $\oplus$ A = 0 |
| Identity | XOR with 0 | A $\oplus$ 0 = A |
The XOR operation is widely used in various fields:
Understanding the properties of XOR is crucial for working with these applications.
The number of distinct Boolean expressions of four variables is-
Which of the following types is best suited to represent the logical values?
In the given circuit, if the input voltage lies between +E1 and -E2, then output is zero.

Input and output characteristics are shown below.

The region between +E1 and -E2 is known as _____.
The minimum number of 2-input NAND gates required to realize the logic function $Y = AB + \bar A \bar B$ is
The theorem to which the given two powerful laws in Boolean algebra belong to, is:
Law 1:\(\overline{A + B} = \overline A \ \overline B\)
Law 2:\(\overline{A B} = \overline A \ + \overline B\)