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Question

$-273.15^\circ\text{C}$ temperature is equal to:

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
$0\text{ K}$

Celsius to Kelvin Temperature Conversion

The question requires converting a given temperature from Celsius ($^\circ\text{C}$) to the Kelvin (K) scale.

Conversion Formula

The relationship between the Celsius scale and the Kelvin scale is defined by the formula:

$ T_\text{K} = T_\text{C} + 273.15 $

Here, $T_\text{K}$ represents the temperature in Kelvin and $T_\text{C}$ represents the temperature in Celsius.

Calculation

The given temperature is:

$ T_\text{C} = -273.15^\circ\text{C} $

Substitute this value into the conversion formula:

$ T_\text{K} = (-273.15) + 273.15 $

Performing the addition:

$ T_\text{K} = 0 \text{ K} $

Result

The temperature $-273.15^\circ\text{C}$ is equivalent to $0 \text{ K}$.

This specific temperature, $0 \text{ K}$, is recognized as absolute zero, the lowest possible temperature theoretically achievable.

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