\(\frac{(0.05)^2+(0.41)^2+(0.073)^2}{(0.005)^2+(0.041)^2+(0.0073)^2}=\)
100
This problem requires us to simplify a fraction containing the squares of several decimal numbers. We need to evaluate the expression:
$$ \frac{(0.05)^2+(0.41)^2+(0.073)^2}{(0.005)^2+(0.041)^2+(0.0073)^2} $$Let's analyze the relationship between the numbers in the numerator and the denominator.
Observe the numbers involved:
We can see that each number in the denominator is exactly one-tenth (1/10) of the corresponding number in the numerator:
Now, let's substitute these relationships into the squares in the denominator:
Now substitute these back into the original fraction:
$$ \frac{(0.05)^2+(0.41)^2+(0.073)^2}{\frac{(0.05)^2}{100} + \frac{(0.41)^2}{100} + \frac{(0.073)^2}{100}} $$Notice that the denominator has a common factor of $\frac{1}{100}$. Let's factor it out:
$$ \frac{(0.05)^2+(0.41)^2+(0.073)^2}{\frac{1}{100} \left( (0.05)^2+(0.41)^2+(0.073)^2 \right)} $$Let the sum of the squares in the numerator be represented by 'S':
$$ S = (0.05)^2+(0.41)^2+(0.073)^2 $$The expression now becomes:
$$ \frac{S}{\frac{1}{100} S} $$To simplify this complex fraction, we multiply the numerator by the reciprocal of the denominator:
$$ S \times \frac{100}{S} $$The 'S' terms cancel out, leaving:
$$ 100 $$The simplified value of the given fraction is 100. This corresponds to the third option.
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