Yayati sold an item at a loss of 13%, If he had sold it for Rs. 49 more, he would have made a profit of 22%. What should be the selling price of the item to gain a profit of 30%?
Rs. 182
This question involves calculating the selling price of an item under different profit and loss scenarios. We are given information about a sale at a loss, and how the selling price changes to achieve a profit. We need to find the cost price first, and then calculate the selling price required for a specific profit percentage.
Let's denote the Cost Price (CP) of the item by \( C \). The selling price is calculated based on this cost price and the profit or loss percentage.
When the item is sold at a loss of 13%, the selling price (SP1) is 13% less than the cost price.
SP1 = \( C - 13\% \text{ of } C \)
SP1 = \( C - 0.13C \)
SP1 = \( 0.87C \)
If the item had been sold for Rs. 49 more than SP1, the new selling price (SP2) would have resulted in a profit of 22%. The selling price with a 22% profit is 22% more than the cost price.
SP2 = \( C + 22\% \text{ of } C \)
SP2 = \( C + 0.22C \)
SP2 = \( 1.22C \)
According to the problem, SP2 is Rs. 49 more than SP1.
SP2 = SP1 + 49
Substituting the expressions for SP1 and SP2 in terms of \( C \):
\( 1.22C = 0.87C + 49 \)
Now, we can solve this equation to find the value of \( C \).
\( 1.22C - 0.87C = 49 \)
\( (1.22 - 0.87)C = 49 \)
\( 0.35C = 49 \)
\( C = \frac{49}{0.35} \)
To simplify the division, we can write 0.35 as \( \frac{35}{100} \):
\( C = \frac{49}{\frac{35}{100}} = \frac{49 \times 100}{35} \)
Now, simplify the fraction:
\( C = \frac{49}{35} \times 100 = \frac{7 \times 7}{5 \times 7} \times 100 = \frac{7}{5} \times 100 \)
\( C = 7 \times \frac{100}{5} = 7 \times 20 \)
\( C = 140 \)
So, the Cost Price of the item is Rs. 140.
We need to find the selling price required to gain a profit of 30%. This means the selling price (SP3) should be 30% more than the cost price.
SP3 = \( C + 30\% \text{ of } C \)
SP3 = \( C + 0.30C \)
SP3 = \( 1.30C \)
Substitute the calculated value of \( C = 140 \):
SP3 = \( 1.30 \times 140 \)
SP3 = \( 1.3 \times 140 \)
SP3 = \( 182 \)
Therefore, the selling price of the item should be Rs. 182 to gain a profit of 30%.
| Description | Formula / Value |
|---|---|
| Initial Loss Percentage | 13% |
| Initial SP (SP1) | \( 0.87C \) |
| Profit Percentage (New) | 22% |
| New SP (SP2) | \( 1.22C \) |
| Difference in SPs | SP2 - SP1 = Rs. 49 |
| Equation | \( 1.22C - 0.87C = 49 \) |
| Cost Price (C) | Rs. 140 |
| Desired Profit Percentage | 30% |
| Selling Price for 30% Profit (SP3) | \( 1.30C = 1.30 \times 140 = 182 \) |
The selling price required to achieve a 30% profit is Rs. 182.
| Term | Definition | Calculation |
|---|---|---|
| Cost Price (CP) | Original price of the item. | Base for profit/loss calculation. |
| Selling Price (SP) | Price at which item is sold. | SP = CP + Profit; SP = CP - Loss |
| Profit | When SP > CP. | Profit = SP - CP |
| Loss | When SP < CP. | Loss = CP - SP |
| Profit % | Profit as a percentage of CP. | \( \frac{\text{Profit}}{\text{CP}} \times 100 \) |
| Loss % | Loss as a percentage of CP. | \( \frac{\text{Loss}}{\text{CP}} \times 100 \) |
Understanding the relationship between CP, SP, and percentage profit/loss is fundamental. We can express SP directly using percentages:
In this problem, the difference in selling prices corresponds to the combined percentage change from -13% to +22%, which is \( 22\% - (-13\%) = 35\% \). This 35% of the cost price is equal to the Rs. 49 difference in selling price. So, \( 35\% \text{ of } CP = 49 \), which leads to \( 0.35 \times CP = 49 \), and \( CP = \frac{49}{0.35} = 140 \).
Once the cost price is known, calculating the selling price for any desired profit percentage is straightforward using the formula SP = \( \text{CP} \times (1 + \frac{\text{Desired Profit}\%}{100}) \). For a 30% profit, SP = \( 140 \times (1 + \frac{30}{100}) = 140 \times 1.30 = 182 \).
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