The work done in carrying a block of mass 30 kg to a height of ‘X’ m is 6000 J. What will be the value of X (in m)? (Take the value of \(g = 10\ \text{m/s}^2\))
20
Lifting a block against gravity stores energy as gravitational potential energy, so the work done equals the gain in potential energy: \(W = mgh\), where \(m\) is the mass, \(g\) is the acceleration due to gravity and \(h\) is the height (here written as \(X\)).
Substitute the given values: \(6000 = 30 \times 10 \times X\).
So \(6000 = 300\,X\), which gives \(X = \dfrac{6000}{300} = 20\).
Hence, the height X is 20 m.
Similar Questions
Which of the following statement(s) is /are true regarding the work done by a constant force acting on a body?
(i) The work done by the force can never be zero.
(ii) If the direction of the force and displacement of the body is same, the work done will be positive.
(iii) The S.I. unit of work done is joule.
A stone of mass 500g is raised from ground to a height of 20 m. What is the gain in its potential energy?
(Take g=10 m/s2)
Important Questions from Work Power and Energy
A boy raises a box with a weight of 120 N from a height of 2 m. The work done by him is ________.
While releasing the arrow from a stretched bow, the Potential Energy of the bow is converted into?
Which is the main source of almost all energy on Earth?
Area under constant velocity – time curve equals ________ of the object over a given time interval.
If a body of mass is m, linear momentum is p and kinetic energy is K, then which of the following expressions is true?
