The work done in carrying a block of mass 30 kg to a height of ‘X’ m is 6000 J. What will be the value of X (in m)? (Take the value of \(g = 10\ \text{m/s}^2\))
20
Lifting a block against gravity stores energy as gravitational potential energy, so the work done equals the gain in potential energy: \(W = mgh\), where \(m\) is the mass, \(g\) is the acceleration due to gravity and \(h\) is the height (here written as \(X\)).
Substitute the given values: \(6000 = 30 \times 10 \times X\).
So \(6000 = 300\,X\), which gives \(X = \dfrac{6000}{300} = 20\).
Hence, the height X is 20 m.
Important Questions from Work Power and Energy
A boy raises a box with a weight of 120 N from a height of 2 m. The work done by him is ________.
While releasing the arrow from a stretched bow, the Potential Energy of the bow is converted into?
Which is the main source of almost all energy on Earth?
Area under constant velocity – time curve equals ________ of the object over a given time interval.
If a body of mass is m, linear momentum is p and kinetic energy is K, then which of the following expressions is true?
