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Question

With what do you divide thrust in a liquid to obtain the value of pressure?

This question was previously asked in
SSC CGL 2020 Tier-II (English) Previous Year Paper (29-Jan-2022)
The correct answer is

Area

Understanding Pressure from Thrust in Liquids

The question asks what we need to divide 'thrust' by in a liquid to get the value of 'pressure'. This relates directly to the fundamental definition of pressure in physics.

What is Thrust?

In physics, particularly when dealing with fluids (liquids or gases), 'thrust' is often used to describe a force acting perpendicular to a surface. It is essentially the total force exerted by the fluid on that surface.

What is Pressure?

Pressure is defined as the force acting perpendicularly per unit area of a surface. It describes how concentrated the force is over a given area.

The formula for pressure is:

\( P = \frac{F}{A} \)

Where:

  • \( P \) is Pressure
  • \( F \) is the Force acting perpendicular to the surface
  • \( A \) is the Area over which the force acts

Connecting Thrust, Force, and Pressure

Since thrust is the force acting perpendicularly on a surface in a liquid, we can substitute 'Thrust' for 'Force' (\(F\)) in the pressure formula. So, for a liquid:

\( \text{Pressure} = \frac{\text{Thrust}}{\text{Area}} \)

This formula clearly shows that to obtain the value of pressure from thrust, you must divide the thrust by the area over which that thrust is distributed.

Analyzing the Options

Let's look at the given options in light of the pressure formula:

  • Mass: Dividing force (thrust) by mass gives acceleration (\(a = F/m\)), not pressure.
  • Density: Density is mass per unit volume (\( \rho = m/V \)). Dividing force by density does not give pressure.
  • Volume: Dividing force by volume does not give pressure.
  • Area: Dividing force (thrust) by area (\( A \)) gives pressure (\( P = \text{Thrust}/A \)). This aligns with the definition.

Therefore, you divide thrust by area to obtain the value of pressure.

Conclusion

Based on the definition and formula for pressure, dividing the thrust (force) by the area over which it acts gives the pressure. This applies universally, including in liquids.

Revision Table: Pressure Calculation

Concept Definition Formula Units (SI)
Force (Thrust) A push or a pull; specifically, thrust is force perpendicular to a surface in fluids. \( F \) or \( \text{Thrust} \) Newtons (N)
Area The extent or measurement of a surface or piece of land. \( A \) Square meters (\( m^2 \))
Pressure Force acting perpendicularly per unit area. \( P = \frac{F}{A} \) or \( P = \frac{\text{Thrust}}{A} \) Pascals (Pa) or \( N/m^2 \)

Additional Information: Pressure in Liquids

Pressure in liquids has some unique characteristics:

  • Pressure at a depth: In a stationary liquid, pressure increases with depth. The formula for pressure at a certain depth \(h\) is \( P = P_0 + \rho gh \), where \(P_0\) is the pressure at the surface, \( \rho \) is the liquid density, \(g\) is the acceleration due to gravity, and \(h\) is the depth.
  • Pressure is exerted in all directions: At any point within a liquid, pressure is exerted equally in all directions.
  • Pressure depends on depth and density: For a given depth, the pressure in a liquid depends only on the density of the liquid and the acceleration due to gravity, not on the shape or size of the container.

Understanding the relationship between thrust, force, area, and pressure is fundamental to studying fluid mechanics.

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