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Question

Which statement best describes a straight line sloping upwards on a distance-time graph for an object moving with uniform speed?

This question was previously asked in
RRB Group D 2025 Question Paper (9-Aug-2026) (Shift 1)
The correct answer is

The object covers equal distances in equal intervals of time

In a distance-time graph, the slope at any point represents the speed of the moving object.

A straight line sloping upwards indicates a constant, unchanging slope, which means the object is covering the same distance in every equal interval of time.

This is the defining characteristic of uniform speed, since speed remains constant only when equal distances are covered in equal time intervals throughout the motion.

Hence, the object covers equal distances in equal intervals of time.

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Similar Questions

  1. Which of the following describes the rate at which an object changes its velocity?

  2. Which statement best describes uniform circular motion in the context of motion and force?

  3. A car moves at a constant speed of 20 m/s for 5 seconds. What is the total distance travelled by the car during this time?

  4. A velocity-time graph for a car moving with uniform velocity starts at t=0 s and ends at t=10 s, always at 5 m/s. What is the shape of the graph?

  5. A cyclist covers a distance of 30 kilometers in 1.5 hours. What is the average speed of the cyclist?

  6. Which of the following statements best defines uniform circular motion?

  7. What is required to fully describe the displacement of a moving body?

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  9. Which statement correctly describes the difference between position vector and displacement vector?

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Important Questions from Motion in a Straight Line

  1. Which of the following examples represents motion along a straight line?
  2. Ram records the odometer readings of his car for the distance covered from 2000 km at the start of his journey and 2400 km at the end of the journey after 8 hours. What is the average speed of the car?

  3. A body moves along a straight line with displacement \(s = 4t^2 + 2ts =4t^2+2ts=4t^2+2t\) (in m, t in s). Its instantaneous acceleration is:

  4. The area under a velocity-time graph between two instants represents:

  5. A body is dropped freely from a height 'X' m. If tit takes Y seconds to reach the ground. The time it takes to reach half of the height of the tower is (Take g = 10m/s2)

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