A body moves along a straight line with displacement \(s = 4t^2 + 2ts =4t^2+2ts=4t^2+2t\) (in m, t in s). Its instantaneous acceleration is:
Constant \(8 \, m/s^2\)
Differentiating the displacement equation \(s = 4t^2 + 2t\) once gives velocity \(v = 8t + 2\), and differentiating again gives acceleration \(a = 8 \, m/s^2\), which does not depend on time. Hence the body moves with a constant acceleration of 8 m/s2.
The area under a velocity-time graph between two instants represents:
Ram records the odometer readings of his car for the distance covered from 2000 km at the start of his journey and 2400 km at the end of the journey after 8 hours. What is the average speed of the car?
The area under a velocity-time graph between two instants represents:
A body is dropped freely from a height 'X' m. If tit takes Y seconds to reach the ground. The time it takes to reach half of the height of the tower is (Take g = 10m/s2)
Which of the following describes the rate at which an object changes its velocity?