Which one of the following represents the electron occupancy for a superconductor in its normal and superconducting states?

The question asks to identify the correct representation of electron occupancy for a superconductor in its normal and superconducting states.
In a normal metal (above the critical temperature, Tc), electrons occupy energy states according to the Fermi-Dirac distribution. The density of states (DOS), N(E), represents the number of available electron states per unit energy. For many metals, the DOS near the Fermi level (EF) is continuous.
Below Tc, electrons form Cooper pairs, leading to the opening of a superconducting energy gap, $ \Delta $, centered around the Fermi level (EF). This phenomenon is described by the Bardeen-Cooper-Schrieffer (BCS) theory.
Option B correctly depicts the density of states for a superconductor. It shows:
The other options do not accurately represent the gap formation and the resulting density of states modification characteristic of the superconducting transition.
Therefore, the image corresponding to Option B illustrates the electron occupancy in the normal and superconducting states.
Consider a metal-superconductor junction connected to a dc voltage $V$. At $T < T_c$, where $T_c$ is the superconductor's transition temperature, the current $I$ versus $V$ behavior of this junction is shown schematically in the figure below. If the superconducting energy gap is $D \text{ meV}$. The value of $D$ (rounded off to one decimal place) is _____
The figure schematically shows the $M$ (magnetization) - $H$ (magnetic field) plots for certain types of materials. Here $M$ and $H$ are plotted in the same scale and units. Which one of the following is the most appropriate combination?