To determine which molecular orbital is formed by the combination of two \(2p\) orbitals as shown in the diagram, we must consider the orientation and phase of their overlap.

1. In the given diagram, the lobes of the \(2p\) orbitals are aligned parallel to each other, suggesting a lateral overlap.
2. Since the orbitals are out of phase (one lobe shaded differently from the other), this indicates an antibonding interaction.
3. Such an out-of-phase lateral overlap of \(p\) orbitals results in the formation of an antibonding \(\pi^*\) molecular orbital.

Conclusion: The correct answer is the antibonding \(\pi^*\) molecular orbital. This choice is justified based on the out-of-phase lateral overlap, which is characteristic of antibonding \(\pi\) molecular orbitals.

Other Options Explanation:

• Bonding \(\pi\) molecular orbital: This would involve in-phase overlap, not observed here.
• Bonding \(\sigma\) molecular orbital: This would involve end-to-end overlap of orbitals, which is not the case in the diagram.
• Antibonding \(\sigma^*\) molecular orbital: This would also involve end-to-end overlap but out-of-phase, not matching the diagram.