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Question

Which of the following statements regarding electron configuration of atoms is/are correct? 

1. Principal quantum number = 1, K shell, example : He 
2. Principal quantum number = 3, M shell, example : Ne 
3. Principal quantum number = 2, L shell, example : F 
4. Principal quantum number = 3, K shell, example : Si 

Select the answer using the code given below :

The correct answer is
1 and 3 only

Understanding Electron Configuration and Quantum Numbers

This question involves understanding the relationship between electron configurations, principal quantum numbers, and atomic shells (K, L, M...). The principal quantum number, denoted by $n$, describes the main energy level or shell of an electron.

  • $n=1$ corresponds to the K shell.
  • $n=2$ corresponds to the L shell.
  • $n=3$ corresponds to the M shell.
  • And so on...

We need to evaluate each statement based on these principles and the electron configurations of the given elements.

Analyzing the Statements on Electron Configuration

Statement 1: Principal quantum number = 1, K shell, example : He

Analysis: The principal quantum number $n=1$ indeed represents the K shell. Helium (He) is the first element with atomic number 2. Its electron configuration is $1s^2$. All electrons in Helium are in the first energy level ($n=1$), which is the K shell. This statement is correct.

Statement 2: Principal quantum number = 3, M shell, example : Ne

Analysis: The principal quantum number $n=3$ represents the M shell. Neon (Ne) has atomic number 10, and its electron configuration is $1s^2 2s^2 2p^6$. The outermost electrons in Neon are in the L shell ($n=2$), not the M shell ($n=3$). The M shell starts filling after the L shell is completely filled. Therefore, this statement is incorrect.

Statement 3: Principal quantum number = 2, L shell, example : F

Analysis: The principal quantum number $n=2$ represents the L shell. Fluorine (F) has atomic number 9. Its electron configuration is $1s^2 2s^2 2p^5$. The outermost electrons in Fluorine are located in the second energy level ($n=2$), which is the L shell. This statement is correct.

Statement 4: Principal quantum number = 3, K shell, example : Si

Analysis: The principal quantum number $n=3$ corresponds to the M shell, not the K shell. The K shell is defined by $n=1$. Silicon (Si) has atomic number 14, and its electron configuration is $1s^2 2s^2 2p^6 3s^2 3p^2$. While Silicon does have electrons in the M shell ($n=3$), the statement incorrectly associates $n=3$ with the K shell. Therefore, this statement is incorrect.

Conclusion on Electron Configuration Statements

Based on the analysis, statements 1 and 3 are correct descriptions relating principal quantum number, shell name, and an example element's electron distribution.

  • Statement 1: Correct (He: $n=1$, K shell)
  • Statement 2: Incorrect (Ne's outer electrons are in L shell, $n=2$)
  • Statement 3: Correct (F: $n=2$, L shell)
  • Statement 4: Incorrect ($n=3$ is M shell, not K shell)

Therefore, the correct statements are 1 and 3 only.

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Important Questions from Quantum chemistry

  1. Radial distribution function does NOT depend upon
  2. Which one of the following statements regarding wave functions is NOT correct?
  3. Which one of the following molecular orbitals will be formed by combination of the two $2p$ orbitals as shown below ? 

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