Which one of the following is the value of 1 KWh of energy converted into joules?
3.6 × 10 6J
The question asks us to find the equivalent energy value of 1 kilowatt-hour (KWh) when converted into joules (J). Both kilowatt-hour and joule are units of energy, but they belong to different systems or are commonly used in different contexts (KWh for electrical energy billing, joules in physics and SI units).
To perform this conversion, we need to understand the relationship between power, energy, and time. Power is the rate at which energy is transferred or used. The formula linking these is:
\(\text{Energy} = \text{Power} \times \text{Time}\)
We want to convert 1 kilowatt-hour (1 KWh) into joules (J). Using the formula Energy = Power \(\times\) Time, and substituting the values in terms of SI units (Watts and seconds):
\(1 \text{ KW} = 1000 \text{ W}\)
\(1 \text{ h} = 3600 \text{ s}\)
\(\text{Energy (in joules)} = \text{Power (in watts)} \times \text{Time (in seconds)}\)
\(1 \text{ KWh} = (1 \text{ KW}) \times (1 \text{ h})\)
\(1 \text{ KWh} = (1000 \text{ W}) \times (3600 \text{ s})\)
\(1000 \times 3600 = 3,600,000\)
\(1 \text{ KWh} = 3,600,000 \text{ Ws} = 3,600,000 \text{ J}\)
\(3,600,000 \text{ J} = 3.6 \times 10^6 \text{ J}\)
Therefore, 1 kilowatt-hour of energy is equal to 3.6 \(\times\) 10\(^6\) joules.
Let's compare our calculated value with the given options:
| Option | Value in Joules |
|---|---|
| 1 | \(1.8 \times 10^6 \text{ J}\) |
| 2 | \(3.6 \times 10^6 \text{ J}\) |
| 3 | \(6.0 \times 10^6 \text{ J}\) |
| 4 | \(7.2 \times 10^6 \text{ J}\) |
Our calculated value, \(3.6 \times 10^6 \text{ J}\), matches Option 2.
| Unit | Equivalent in SI Units | Notes |
|---|---|---|
| 1 Watt (W) | 1 J/s | SI unit of power |
| 1 Kilowatt (KW) | 1000 W | Common unit of power |
| 1 Joule (J) | 1 W \(\times\) s | SI unit of energy |
| 1 Kilowatt-hour (KWh) | 1 KW \(\times\) 1 h | Common unit of electrical energy |
| 1 KWh (conversion) | \(3.6 \times 10^6\) J | \(1000 \text{ W} \times 3600 \text{ s}\) |
Energy can be expressed in various units depending on the context. Besides joules and kilowatt-hours, other units include:
The conversion between different energy units is crucial in physics and engineering to ensure consistent calculations and understanding across different scales and applications.
Which of the following is correct regarding electric power?
An elevator weighing 400 kg is to be lifted up at a constant velocity of 0.20 m/s. What would be the minimum horsepower of the motor to be used? (g = 9.8 m/s 2and there is no frictional loss)
An elevator weighing 500 kg is to be lifted up at a constant velocity of 0.25 m/s. What would be the minimum horsepower of the motor to be used? G = 9.8 m/s2 and there is no frictional loss.
Units of power is:
One horse power is equal to