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Question

Which one of the following general electronic configurations correctly represent a transition metal element?

This question was previously asked in
CDS 2 2025 Maths Question Paper (14-Sep-2025)
The correct answer is
\((n-1)d^{1-10}ns^{0-2}\)

Transition Metal Electronic Configuration Fundamentals

Transition metal elements are a fascinating group found in the d-block of the periodic table. Their identity is primarily linked to the way their electrons are arranged, specifically concerning the 'd' orbitals.

Defining Transition Metals

The core characteristic that defines a transition metal is having incompletely filled d sub-shells in their neutral atomic state or in common oxidation states. This means that electrons are actively being added to the d orbitals of the penultimate energy shell (the shell just before the outermost one).

Analyzing Electronic Configuration Options

Let's examine each provided general electronic configuration to see which one accurately represents a transition metal:

  • Option 1: \((n-2)d^{1-10}ns^2\)

    This configuration is incorrect because it suggests that the d-orbitals of the \((n-2)\) shell are being filled. For transition metals, it's the \((n-1)\) shell's d-orbitals that are typically involved.

  • Option 2: \((n-2)f^{1-14}(n-1)d^{0-1}ns^2\)

    This configuration involves the filling of \(f\) orbitals (\((n-2)f^{1-14}\)), which are characteristic of the lanthanide and actinide series (f-block elements), not the d-block transition metals.

  • Option 3: \(ns^2np^6nd^{1-10}\)

    This configuration is inaccurate. The filling of the \(nd\) subshell after the \(ns\) and \(np\) subshells of the same principal energy level (\(n\)) is not typical for transition metals. Furthermore, a filled \(ns^2np^6\) configuration often signifies a noble gas electron arrangement.

  • Option 4: \((n-1)d^{1-10}ns^{0-2}\)

    This is the correct general electronic configuration for transition metals.

    • \((n-1)d^{1-10}\): This part accurately shows that the d-orbitals of the penultimate shell (one shell less than the outermost, \(n\)) are being filled with electrons, ranging from 1 to 10. This is the defining feature.
    • \(ns^{0-2}\): This part indicates that the outermost shell's s-orbitals contain 0 to 2 electrons. This accounts for cases where the outermost s-orbital might be empty (like in Palladium, Pd: \([Kr] 4d^{10} 5s^0\)) or contain two electrons (like in Scandium, Sc: \([Ar] 4s^2 3d^1\)), or even one electron (like in Chromium, Cr: \([Ar] 4s^1 3d^5\)).
  • Option 5: (No configuration provided)

Conclusion on Transition Metal Configuration

Based on the analysis, the electronic configuration that correctly represents a transition metal element involves the filling of the \((n-1)d\) subshell while the outermost \(ns\) subshell contains 0 to 2 electrons. This matches Option 4.

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