A. Millisecond
B. Picosecond
C. Nanosecond
D. Microsecond
E. Second
Choose the correct answer from the options given below:
Memory access time refers to the duration it takes for a processor to read data from or write data to a memory location. This time is typically measured in very small units of time. Understanding the relative sizes of these units is crucial for comprehending memory performance.
Let's compare the given units of time to determine their order from largest to smallest:
Based on their values in seconds, we can order these units from the largest magnitude to the smallest:
| Unit Name | Abbreviation | Value in Seconds | Order (Largest to Smallest) |
|---|---|---|---|
| Second | s | $1 \text{ s}$ | 1 (Largest) |
| Millisecond | ms | $10^{-3} \text{ s}$ | 2 |
| Microsecond | $\mu$s | $10^{-6} \text{ s}$ | 3 |
| Nanosecond | ns | $10^{-9} \text{ s}$ | 4 |
| Picosecond | ps | $10^{-12} \text{ s}$ | 5 (Smallest) |
Therefore, the correct sequence of memory access time units from largest to smallest is:
Second (E) > Millisecond (A) > Microsecond (D) > Nanosecond (C) > Picosecond (B)
This sequence corresponds to the order E, A, D, C, B.
Suppose that the register A and register K have the bit configuration. Only the three leftmost bits of A are compared with memory words because K has 1's in these positions. Because of its organization, this type of memory is uniquely suited to parallel searches by data association. This type of memory is known as
Consider a system with 2 level cache. Access times of Level 1, Level 2 cache and main memory are 0.5 ns, 5 ns and 100 ns respectively. The hit rates of Level 1 and Level 2 caches are 0.7 and 0.8 respectively. What is the average access time of the system ignoring the search time within cache?
Related to computers, what is 'Wetware'?
____ number of lines are required to select __________ memory locations.