Which of the following is a velocity-time graph for uniform motion of a car?

The Correct Answer is Option 1 i.e

Calculation of distance using velocity-time graph:
Let two points A and B on the slope of the graph.
Draw two lines parallel to y-axis AC from point A, and BD from point B.(Above Fig.)
Let point D at the x-axis (time axis) is t2 and point C is t1.
Let AB meet at ‘v’ at the y-axis, i.e. object is moving with a velocity, v.
Thus, distance or displacement by the object is equal to the area of the rectangle (shaded) ABCD.
Thus, Area of ABCD = BD × DC
⇒ s = v(t2 - t1)
Since the given object is moving with constant velocity along a straight line, thus displacement will be equal to the distance covered.
Therefore, Distance or Displacement = velocity X time interval.
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The first equation of motion gives the relation between _________.
The rate of change of displacement is called:
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If the distance time graph of the motion of an object is a straight line but not parallel to the time axis, then it may be concluded that the object is moving with a:
Which of the following changes when a body performs uniform circular motion?
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