Which of the following is a product formed at the cathode during the electrolysis of brine?
Hydrogen gas
In the electrolysis of brine (concentrated NaCl solution), water is reduced at the cathode.
Hydrogen gas is released there; chlorine gas is released at the anode, and sodium hydroxide forms near the cathode.
Sodium metal is not formed from an aqueous solution.
Hence, the answer is Hydrogen gas.
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Important Questions from Electrochemistry
- At $298 \, K$, given the standard electrode potentials: $E^\circ_{Cu^{2+}/Cu} = 0.34 \, V$, $E^\circ_{Zn^{2+}/Zn} = -0.76 \, V$, $E^\circ_{Fe^{2+}/Fe} = -0.44 \, V$, and $E^\circ_{Ag^{+}/Ag} = 0.80 \, V$.
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The mobility of a divalent cation in water is 8 × 10-8 m2 V-1 s-1. The effective radius of the ion is (viscosity of water = 1 cP : c = 1.6 × 10-19 C)
The electrical double layer model among the following that consists of both fixed and diffuse layers is
