Which of the following best describes the shape of a distance-time graph for an object moving at a uniform speed?
A straight line with a constant slope
On a distance-time graph, time is plotted along the horizontal axis and distance along the vertical axis, and the slope of the graph at any point gives the speed of the body.
When an object moves with uniform speed, it covers equal distances in equal intervals of time, so the ratio of distance to time stays the same throughout the motion.
This constant rate of change produces a straight line that rises steadily, that is, a straight line with a constant slope; a curved line would indicate changing speed, and a horizontal line would mean the body is at rest.
Hence, the correct answer is A straight line with a constant slope.
Which of the following describes the rate at which an object changes its velocity?
Which statement best describes uniform circular motion in the context of motion and force?
A car moves at a constant speed of 20 m/s for 5 seconds. What is the total distance travelled by the car during this time?
A velocity-time graph for a car moving with uniform velocity starts at t=0 s and ends at t=10 s, always at 5 m/s. What is the shape of the graph?
A cyclist covers a distance of 30 kilometers in 1.5 hours. What is the average speed of the cyclist?
Which of the following statements best defines uniform circular motion?
What is required to fully describe the displacement of a moving body?
On a velocity-time graph, what does a horizontal straight line above the time axis indicate about the motion of the object?
Which statement correctly describes the difference between position vector and displacement vector?
Which of the following best describes the appearance of a distance-time graph for an object moving at a uniform speed?
Ram records the odometer readings of his car for the distance covered from 2000 km at the start of his journey and 2400 km at the end of the journey after 8 hours. What is the average speed of the car?
A body moves along a straight line with displacement \(s = 4t^2 + 2ts =4t^2+2ts=4t^2+2t\) (in m, t in s). Its instantaneous acceleration is:
The area under a velocity-time graph between two instants represents:
A body is dropped freely from a height 'X' m. If tit takes Y seconds to reach the ground. The time it takes to reach half of the height of the tower is (Take g = 10m/s2)