Which composite number can divide the sum of the first 12 natural numbers?
6
The correct answer is "6." The sum of the first 12 natural numbers is 78, and 6 is the composite number that divides 78.
If m and n are two positive real numbers such that 9m2 + n2 = 40 and mn = 4, then the value of 3m + n is:
Consider the following statements :
1. If n is a natural number, then the number \(\frac{n\left(n^2+2\right)}{3}\) is also a natural number.
2. If m is an odd integer, then the number \(\frac{\mathrm{m}^4+4 \mathrm{~m}^2+11}{16}\) is an integer.
Which of the statements given above is/are correct ?
If 1 is added to the greatest 7-digit number, it will be equal to
The largest 5-digit number having three different digits is
The product of successor and predecessor of 999 is