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Question

When no ac input signals are connected to CE Transistor Load line can be plotted ______

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is VCE vs Ic

Understanding the CE Transistor Load Line

The load line in a transistor circuit is a graphical representation of the relationship between the collector current (\(I_c\)) and the collector-emitter voltage (\(V_{CE}\)) that is determined by the external circuit components, specifically the collector resistor (\(R_c\)) and the collector supply voltage (\(V_{CC}\)). When we talk about the DC load line, we are considering the circuit's behavior under steady-state conditions, without any AC input signals changing the operating point dynamically.

DC Load Line Analysis for CE Transistor

For a simple Common Emitter (CE) transistor configuration powered by a DC voltage source \(V_{CC}\) and having a collector resistor \(R_c\), we can analyze the output loop (collector-emitter loop) using Kirchhoff's Voltage Law. The voltage across the collector resistor is \(I_c R_c\), and the voltage across the transistor itself is \(V_{CE}\). The total voltage supplied is \(V_{CC}\). Therefore, the equation for the output loop is:

\[ V_{CC} = I_c R_c + V_{CE} \]

This equation describes all possible combinations of \(I_c\) and \(V_{CE}\) for the given external circuit components (\(V_{CC}\) and \(R_c\)). This is a linear equation. If we rearrange it to express \(I_c\) in terms of \(V_{CE}\), it looks like this:

\[ I_c = -\frac{1}{R_c} V_{CE} + \frac{V_{CC}}{R_c} \]

This equation is in the standard form of a linear equation \(y = mx + c\), where \(y = I_c\) and \(x = V_{CE}\). The slope of the line is \(-\frac{1}{R_c}\), and the y-intercept (where \(V_{CE} = 0\)) is \(\frac{V_{CC}}{R_c}\). The x-intercept (where \(I_c = 0\)) can be found by setting \(I_c = 0\) in the original equation: \(V_{CC} = 0 \cdot R_c + V_{CE}\), which gives \(V_{CE} = V_{CC}\).

The DC load line is a straight line drawn on the transistor's output characteristic curves (which plot \(I_c\) vs \(V_{CE}\) for different values of base current \(I_b\)). This line connects the two points determined by the external circuit:

  • Point 1 (Y-intercept): \(V_{CE} = 0\), \(I_c = \frac{V_{CC}}{R_c}\) (Represents saturation)
  • Point 2 (X-intercept): \(I_c = 0\), \(V_{CE} = V_{CC}\) (Represents cutoff)

Any valid DC operating point (Q-point) for the transistor must lie on this load line.

Evaluating Options for CE Load Line Plot

Let's examine the given options based on our understanding of the DC load line:

  • Option 1: VCE vs VCC
    This is incorrect. \(V_{CC}\) is the constant supply voltage. The load line plots variables (\(I_c\) and \(V_{CE}\)) against each other, not a variable against a constant.
  • Option 2: VCE vs VEE
    This is incorrect. \(V_{EE}\) is the emitter supply voltage (if used). While \(V_{EE}\) might influence biasing, the primary DC load line for the collector circuit relates \(I_c\) and \(V_{CE}\) based on the collector loop components.
  • Option 3: VCE vs Ib
    This is incorrect for plotting the load line itself. While the transistor's operating point depends on \(I_b\), the load line represents the constraint imposed by the external collector circuit on the relationship between \(I_c\) and \(V_{CE}\). The load line is drawn *on* the \(I_c\) vs \(V_{CE}\) characteristics (plotted for various \(I_b\)), but the load line itself is not a plot of \(V_{CE}\) vs \(I_b\).
  • Option 4: VCE vs Ic
    This is correct. As derived from the output loop equation \(V_{CC} = I_c R_c + V_{CE}\), there is a linear relationship between \(I_c\) and \(V_{CE}\). The load line is the graph of this linear relationship. Although standard plots put the dependent variable (\(I_c\)) on the y-axis and the independent variable (\(V_{CE}\)) on the x-axis, listing them as "VCE vs Ic" still correctly identifies the two quantities being plotted against each other to form the load line.

Conclusion on CE Transistor Load Line Plot

The DC load line for a CE transistor, when no AC input is applied, is a graphical representation of the output loop equation \(V_{CC} = I_c R_c + V_{CE}\). This line is plotted showing the relationship between the collector current (\(I_c\)) and the collector-emitter voltage (\(V_{CE}\)). It is conventionally plotted with \(I_c\) on the y-axis and \(V_{CE}\) on the x-axis, effectively showing \(I_c\) versus \(V_{CE}\).

Revision Table: CE Transistor Load Line

Term Description
DC Load Line A line on the \(I_c\) vs \(V_{CE}\) graph showing possible operating points based on external circuit components (\(R_c\), \(V_{CC}\)).
\(V_{CE}\) Collector-Emitter Voltage, voltage across the transistor's output terminals.
\(I_c\) Collector Current, the current flowing into the collector terminal.
\(V_{CC}\) Collector Supply Voltage, the DC voltage powering the collector circuit.
\(R_c\) Collector Resistor, the resistor connected in series with the collector.

Additional Information on Transistor Operating Point

The DC load line is crucial for determining the DC operating point, also known as the Quiescent point or Q-point, of the transistor. This point represents the DC values of \(I_c\) and \(V_{CE}\) when no AC signal is applied. The Q-point is the intersection of the DC load line and the transistor's output characteristic curve corresponding to the DC base current (\(I_b\)). Setting the Q-point appropriately is essential for ensuring the transistor operates in the active region for linear amplification when an AC signal is applied.

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