What will be the chromosome number in the gamete of fruit fly if its meiocyte has 8 chromosomes?
(b) 4
This question asks about the chromosome number in the gamete of a fruit fly, given the chromosome number in its meiocyte. To answer this, we need to understand the process of cell division that produces gametes.
In sexually reproducing organisms, gametes (like sperm and egg cells) are produced through a special type of cell division called meiosis. Meiosis is a reductional division, meaning it reduces the number of chromosomes by half.
A meiocyte is a cell that is destined to undergo meiosis. Meiocytes are typically diploid cells, meaning they contain two sets of chromosomes (represented as \(\text{2n}\)). One set comes from each parent.
Gametes, on the other hand, are haploid cells. They contain only one set of chromosomes (represented as \(\text{n}\)). When a male gamete (sperm) fuses with a female gamete (egg) during fertilization, the resulting zygote is diploid (\(\text{2n}\)), restoring the original chromosome number.
The question states that the meiocyte of the fruit fly has 8 chromosomes. Since the meiocyte is a diploid cell, its chromosome number is \(\text{2n}\).
So, for the fruit fly:
Gametes are produced from meiocytes through meiosis, which halves the chromosome number. The chromosome number in a gamete is the haploid number (\(\text{n}\)).
To find the haploid number (\(\text{n}\)), we divide the diploid number (\(\text{2n}\)) by 2:
\(\text{n} = \frac{\text{2n}}{2}\)
Substituting the given value:
\(\text{n} = \frac{8}{2}\)
\(\text{n} = 4\)
Therefore, the chromosome number in the gamete of a fruit fly is 4.
| Cell Type | Ploidy Level | Chromosome Number |
|---|---|---|
| Meiocyte (or somatic cell) | Diploid (\(\text{2n}\)) | 8 |
| Gamete (sperm or egg) | Haploid (\(\text{n}\)) | 4 |
Given that the meiocyte has 8 chromosomes (\(\text{2n} = 8\)), the gamete, which is haploid (\(\text{n}\)), will have half the number of chromosomes. Thus, the chromosome number in the gamete is \(8 / 2 = 4\).
| Term | Description | Fruit Fly Chromosome Number |
|---|---|---|
| Meiocyte | Cell undergoing meiosis | 8 (\(\text{2n}\)) |
| Gamete | Sex cell (sperm/egg) | 4 (\(\text{n}\)) |
| Meiosis | Cell division producing gametes (reduces chromosome number) | \(\text{2n} \to \text{n}\) |
Ploidy: Ploidy refers to the number of sets of chromosomes in a cell. Diploid (\(\text{2n}\)) cells have two sets, while haploid (\(\text{n}\)) cells have one set. Most somatic (body) cells in organisms are diploid.
Meiosis: Meiosis is essential for sexual reproduction. It consists of two rounds of division: Meiosis I and Meiosis II.
The outcome of meiosis is four genetically distinct haploid cells (gametes) from a single diploid meiocyte. This reduction in chromosome number ensures that when two gametes fuse during fertilization, the correct diploid number for the species is restored in the offspring.
Fruit flies (\(\textit{Drosophila melanogaster}\)) are often used in genetics research because they reproduce quickly and have easily observable traits and chromosomes.
Match List-I with List-II:
| List-I (Organism) | List-II (Sex Chromosomes) |
|---|---|
| (A) Male grasshopper | (I) XY |
| (B) Male Drosophila | (II) XX |
| (C) Female bird | (III) XX |
| (D) Female grasshopper | (IV) XO |
Choose the correct answer from the options given below:
Match List-I with List-II:
| List-I | List-II |
|---|---|
| (A) Bacteriophage lambda | (I) 231 gene |
| (B) Y-chromosome of human | (II) 48502 bp |
| (C) Haploid content of human DNA | (III) 3.3 × 109 bp |
| (D) Escherichia coli DNA | (IV) 4.6 × 106 bp |
Choose the correct answer from the options given below:
Central dogma in molecular biology states that genetic information flows from:
Read the following and select the set of correct statements. (A) Euchromatin is transcriptionally inactive (B) Heterochromatin is more densely packed (C) Heterochromatin is loosely packed (D) Euchromatin is transcriptionally active (E) Euchromatin stains lighter
A double stranded DNA fragment has 500 Adenine bases. If total number of base pairs in this fragment is 2500, then what will be the number of guanine bases?