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Question

Central dogma in molecular biology states that genetic information flows from:

The correct answer is

(b) DNA → mRNA → Protein

Understanding the Central Dogma of Molecular Biology

The central dogma of molecular biology is a fundamental principle that describes the flow of genetic information within a biological system. It explains how the instructions encoded in DNA are converted into functional products, primarily proteins.

Key Processes in Central Dogma

The central dogma outlines the typical sequence of events in gene expression:

  • Replication: The process by which DNA makes copies of itself. This ensures that genetic information is passed accurately from one generation of cells to the next. The flow here is DNA → DNA.
  • Transcription: The process where the genetic information stored in DNA is copied into a messenger RNA (mRNA) molecule. This occurs in the nucleus of eukaryotic cells. The flow here is DNA → mRNA.
  • Translation: The process where the sequence of codons in the mRNA molecule is used to synthesize a specific sequence of amino acids, forming a protein. This occurs in ribosomes in the cytoplasm. The flow here is mRNA → Protein.

Therefore, the main flow of genetic information described by the central dogma is DNA → mRNA → Protein.

Analyzing the Options for Central Dogma

Let's evaluate each provided option based on the principles of the central dogma:

  • (a) DNA → DNA → Lipid: This option includes replication (DNA → DNA) but then suggests a flow to Lipid. Lipids are not directly synthesized from genetic information in this manner described by the central dogma. This flow is incorrect.
  • (b) DNA → mRNA → Protein: This sequence represents transcription (DNA → mRNA) followed by translation (mRNA → Protein). This is the classical pathway described by the central dogma for the expression of genetic information into proteins. This flow is consistent with the central dogma.
  • (c) Protein → mRNA → DNA: This sequence suggests information flow from protein backwards to nucleic acids. While some processes like reverse transcription (RNA → DNA) exist (seen in retroviruses), the flow from protein to RNA or DNA is not part of the central dogma's primary information flow. This flow is incorrect.
  • (d) DNA → Protein → mRNA: This sequence suggests translation from DNA directly to protein, followed by something converting protein back to mRNA. The direct synthesis of protein from DNA does not occur; it requires an mRNA intermediate. The flow from protein to mRNA is also not part of the standard central dogma. This flow is incorrect.

Based on the analysis, the sequence that accurately represents the primary flow of genetic information according to the central dogma is DNA → mRNA → Protein.

Summary of Central Dogma Processes
Process Information Flow Description
Replication DNA → DNA Copying DNA
Transcription DNA → mRNA Synthesizing mRNA from DNA template
Translation mRNA → Protein Synthesizing protein from mRNA template

Revision Table: Central Dogma Concepts

Concept Explanation Key Molecule(s)
Central Dogma Describes the flow of genetic information DNA, RNA, Protein
Replication DNA copying itself DNA polymerase
Transcription DNA to RNA RNA polymerase
Translation RNA to Protein Ribosomes, tRNA

Additional Information: Central Dogma Extensions

While the central dogma states DNA → mRNA → Protein as the main flow, there are some exceptions or additions:

  • Reverse Transcription: Some viruses (like retroviruses, e.g., HIV) can synthesize DNA from an RNA template using an enzyme called reverse transcriptase. This flow is RNA → DNA.
  • RNA Replication: Some viruses use RNA as their genetic material and can replicate RNA directly from an RNA template. This flow is RNA → RNA.

However, even with these additions, the transfer of information from protein back to nucleic acid (DNA or RNA) is not known to occur naturally.

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Important Questions from Molecular Basis of Inheritance

  1. What will be the chromosome number in the gamete of fruit fly if its meiocyte has 8 chromosomes?

  2. Match List-I with List-II:

    List-I (Organism)List-II (Sex Chromosomes)
    (A) Male grasshopper(I) XY
    (B) Male Drosophila(II) XX 
    (C) Female bird(III) XX
    (D) Female grasshopper(IV) XO

    Choose the correct answer from the options given below:

  3. Match List-I with List-II:

    List-IList-II
    (A) Bacteriophage lambda(I) 231 gene
    (B) Y-chromosome of human(II) 48502 bp
    (C) Haploid content of human DNA (III) 3.3 × 109 bp
    (D) Escherichia coli DNA(IV) 4.6 × 106 bp

    Choose the correct answer from the options given below:

  4. Read the following and select the set of correct statements. (A) Euchromatin is transcriptionally inactive (B) Heterochromatin is more densely packed (C) Heterochromatin is loosely packed (D) Euchromatin is transcriptionally active (E) Euchromatin stains lighter

  5. A double stranded DNA fragment has 500 Adenine bases. If total number of base pairs in this fragment is 2500, then what will be the number of guanine bases?

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