Match List-I with List-II: Choose the correct answer from the options given below:List-I (Organism) List-II (Sex Chromosomes) (A) Male grasshopper (I) XY (B) Male Drosophila (II) XX (C) Female bird (III) XX (D) Female grasshopper (IV) XO
(c) (A)-(IV), (B)-(I), (C)-(III), (D)-(II)
Sex chromosomes are special chromosomes that determine the sex of an individual. Different organisms have different systems for sex determination involving these chromosomes. This question asks us to match specific organisms with their respective sex chromosome constitutions.
Let's look at the sex chromosome systems typically found in the organisms listed:
Now let's match the specific individuals mentioned in List-I with the sex chromosomes provided in List-II, based on common biological understanding and the options given:
Based on the analysis, and aligning with the potential matches from the options, the correct pairing is:
| List-I (Organism) | List-II (Sex Chromosomes) | Match |
|---|---|---|
| (A) Male grasshopper | (IV) \(\text{XO}\) | (A) - (IV) |
| (B) Male Drosophila | (I) \(\text{XY}\) | (B) - (I) |
| (C) Female bird | (III) \(\text{XX}\) | (C) - (III) |
| (D) Female grasshopper | (II) \(\text{XX}\) | (D) - (II) |
Let's check the options provided against these matches:
The matching that aligns with the provided choices is (A)-(IV), (B)-(I), (C)-(III), (D)-(II).
It is important to note that while the \(\text{ZW}\) system is standard for birds, the provided options use \(\text{XX}\)/\(\text{XY}\)/\(\text{XO}\) notation, and the match given for Female bird in the correct option is \(\text{XX}\). Always follow the specific information provided in the question and options during an exam.
| Organism/Sex | Sex Chromosomes | System Type | Notes |
|---|---|---|---|
| Human Female | \(\text{XX}\) | \(\text{XY}\) | Homogametic |
| Human Male | \(\text{XY}\) | \(\text{XY}\) | Heterogametic |
| Drosophila Female | \(\text{XX}\) | \(\text{XY}\) | Sex determined by X:autosome ratio |
| Drosophila Male | \(\text{XY}\) | \(\text{XY}\) | Sex determined by X:autosome ratio |
| Grasshopper Female | \(\text{XX}\) | \(\text{XO}\) | Homogametic |
| Grasshopper Male | \(\text{XO}\) | \(\text{XO}\) | Heterogametic, missing a chromosome |
| Bird Female | \(\text{ZW}\) | \(\text{ZW}\) | Heterogametic (ZW), lays eggs determining sex |
| Bird Male | \(\text{ZZ}\) | \(\text{ZW}\) | Homogametic (ZZ) |
This table summarizes common sex chromosome systems, including the ZW system found in birds which was relevant to the question but not directly listed in the options' chromosome types.
Sex determination is a fundamental biological process. While chromosomal systems like \(\text{XY}\), \(\text{XO}\), and \(\text{ZW}\) are common, other mechanisms exist, such as environmental sex determination (temperature-dependent in many reptiles) or haplo-diploidy (in bees and ants, where fertilized eggs become females and unfertilized eggs become males).
In the \(\text{XY}\) and \(\text{ZW}\) systems, the heterogametic sex produces two types of gametes regarding sex chromosomes (\(\text{X}\) and \(\text{Y}\), or \(\text{Z}\) and \(\text{W}\)), while the homogametic sex produces only one type (\(\text{X}\) or \(\text{Z}\)). The interaction or presence of these chromosomes dictates development into male or female.
What will be the chromosome number in the gamete of fruit fly if its meiocyte has 8 chromosomes?
Match List-I with List-II:
| List-I | List-II |
|---|---|
| (A) Bacteriophage lambda | (I) 231 gene |
| (B) Y-chromosome of human | (II) 48502 bp |
| (C) Haploid content of human DNA | (III) 3.3 × 109 bp |
| (D) Escherichia coli DNA | (IV) 4.6 × 106 bp |
Choose the correct answer from the options given below:
Central dogma in molecular biology states that genetic information flows from:
Read the following and select the set of correct statements. (A) Euchromatin is transcriptionally inactive (B) Heterochromatin is more densely packed (C) Heterochromatin is loosely packed (D) Euchromatin is transcriptionally active (E) Euchromatin stains lighter
A double stranded DNA fragment has 500 Adenine bases. If total number of base pairs in this fragment is 2500, then what will be the number of guanine bases?