Direction: Read the following information and answer the three items that follow: Let α = β = 15°.
What is the value of sin α + cos β ?
√3 / √2
The problem asks for the value of \(\sin \alpha + \cos \beta\), given that \(\alpha = \beta = 15^\circ\). This means we need to find the value of \(\sin 15^\circ + \cos 15^\circ\).
To solve this, we first need to determine the values of \(\sin 15^\circ\) and \(\cos 15^\circ\). These values can be found using trigonometric identities for differences of angles. We know that \(15^\circ = 45^\circ - 30^\circ\).
We use the sine subtraction formula: \(\sin(A - B) = \sin A \cos B - \cos A \sin B\).
Let \(A = 45^\circ\) and \(B = 30^\circ\).
So, \(\sin 15^\circ = \sin(45^\circ - 30^\circ) = \sin 45^\circ \cos 30^\circ - \cos 45^\circ \sin 30^\circ\).
We know the standard values for \(45^\circ\) and \(30^\circ\):
Substitute these values into the formula:
\(\sin 15^\circ = \left(\frac{1}{\sqrt{2}}\right)\left(\frac{\sqrt{3}}{2}\right) - \left(\frac{1}{\sqrt{2}}\right)\left(\frac{1}{2}\right)\)
\(\sin 15^\circ = \frac{\sqrt{3}}{2\sqrt{2}} - \frac{1}{2\sqrt{2}}\)
\(\sin 15^\circ = \frac{\sqrt{3}-1}{2\sqrt{2}}\)
We use the cosine subtraction formula: \(\cos(A - B) = \cos A \cos B + \sin A \sin B\).
Let \(A = 45^\circ\) and \(B = 30^\circ\).
So, \(\cos 15^\circ = \cos(45^\circ - 30^\circ) = \cos 45^\circ \cos 30^\circ + \sin 45^\circ \sin 30^\circ\).
Substitute the standard values:
\(\cos 15^\circ = \left(\frac{1}{\sqrt{2}}\right)\left(\frac{\sqrt{3}}{2}\right) + \left(\frac{1}{\sqrt{2}}\right)\left(\frac{1}{2}\right)\)
\(\cos 15^\circ = \frac{\sqrt{3}}{2\sqrt{2}} + \frac{1}{2\sqrt{2}}\)
\(\cos 15^\circ = \frac{\sqrt{3}+1}{2\sqrt{2}}\)
Now we add the values we found for \(\sin 15^\circ\) and \(\cos 15^\circ\):
\(\sin 15^\circ + \cos 15^\circ = \frac{\sqrt{3}-1}{2\sqrt{2}} + \frac{\sqrt{3}+1}{2\sqrt{2}}\)
\(= \frac{(\sqrt{3}-1) + (\sqrt{3}+1)}{2\sqrt{2}}\)
\(= \frac{\sqrt{3} - 1 + \sqrt{3} + 1}{2\sqrt{2}}\)
\(= \frac{2\sqrt{3}}{2\sqrt{2}}\)
\(= \frac{\sqrt{3}}{\sqrt{2}}\)
Alternatively, we can rationalize the denominator by multiplying the numerator and denominator by \(\sqrt{2}\):
\(\frac{\sqrt{3}}{\sqrt{2}} = \frac{\sqrt{3} \times \sqrt{2}}{\sqrt{2} \times \sqrt{2}} = \frac{\sqrt{6}}{2}\)
However, the options are not rationalized, so we should compare our result \(\frac{\sqrt{3}}{\sqrt{2}}\) with the given options.
Comparing our result \(\frac{\sqrt{3}}{\sqrt{2}}\) with the options:
The value of \(\sin 15^\circ + \cos 15^\circ\) is \(\frac{\sqrt{3}}{\sqrt{2}}\).
| Angle | sin | cos | tan |
|---|---|---|---|
| \(0^\circ\) | 0 | 1 | 0 |
| \(30^\circ\) (\(\frac{\pi}{6}\)) | \(\frac{1}{2}\) | \(\frac{\sqrt{3}}{2}\) | \(\frac{1}{\sqrt{3}}\) |
| \(45^\circ\) (\(\frac{\pi}{4}\)) | \(\frac{1}{\sqrt{2}}\) | \(\frac{1}{\sqrt{2}}\) | 1 |
| \(60^\circ\) (\(\frac{\pi}{3}\)) | \(\frac{\sqrt{3}}{2}\) | \(\frac{1}{2}\) | \(\sqrt{3}\) |
| \(90^\circ\) (\(\frac{\pi}{2}\)) | 1 | 0 | Undefined |
Besides difference formulas, there are many other trigonometric identities that are useful for simplifying expressions and solving equations. Some key identities include:
These identities help in calculating trigonometric values for various angles, including \(15^\circ\), \(75^\circ\), etc., by expressing them as sums or differences of standard angles.
The value of \(\sqrt3\) cosec 20° - sec 20° is equal to?
If tan A - tan B = x and cot B - cot A = y, then what is the value of cot (A - B)?
What is sin (α + β) - 2sin α cos β + sin (α - β) equal to?
What is cos 80° + cos 40° - cos 20° equal to?
What is \(\cot \left( \frac{A}{2} \right)-\tan \left( \frac{A}{2} \right)\) equal to?
What is tan25°tan15° + tan15° tan50° + tan25°tan50° equal to?
Tan 54° can be expressed as
What is the value of θ?
What is the value of A?
What is the value of B?
The value of \(\sqrt3\) cosec 20° - sec 20° is equal to?
Find the value of sin 12° sin 48° sin 54°:
The value of sin 10° sin 50° sin 70° is:
The value of sin 36° is?
The value of cos 20° + cos 100° + cos 140° is