To find the value of $101^3$, we can use the algebraic identity for the cube of a binomial: $(a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3$. Let $a=100$ and $b=1$. This method simplifies the calculation.
Apply the binomial cube identity:
$101^3 = (100 + 1)^3$
Substitute $a=100$ and $b=1$ into the formula:
$ (100)^3 + 3(100)^2(1) + 3(100)(1)^2 + (1)^3 $
Calculate each term:
Sum the results:
$ 1,000,000 + 30,000 + 300 + 1 = 1,030,301 $
The value of $101^3$ is $1,030,301$.
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