Question
What is the value of \((0.2^3 + 0.02^3) \div (0.4^3 + 0.04^3)\)?
This question was previously asked in
SSC CGL 2025 Tier 2 Paper 1 Question Paper (19-Jan-2026)
The correct answer is
0.125
Notice that each base in the denominator is exactly twice the matching base in the numerator: \(0.4 = 2(0.2)\) and \(0.04 = 2(0.02)\).
Pull out the factor of \(2^3\) from the denominator:
\(0.4^3 + 0.04^3 = (2 \times 0.2)^3 + (2 \times 0.02)^3 = 8\,(0.2^3) + 8\,(0.02^3) = 8\,(0.2^3 + 0.02^3)\)
Take the ratio:
\(\dfrac{0.2^3 + 0.02^3}{0.4^3 + 0.04^3} = \dfrac{0.2^3 + 0.02^3}{8\,(0.2^3 + 0.02^3)} = \dfrac{1}{8} = 0.125\)
Hence the value is 0.125 — option (3).
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