What is the unit place digit in the expansion of 7 73 ?
7
To find the unit digit of a number raised to a large power, we look for the pattern of the unit digits of the base number raised to successive powers.
Let's find the pattern of the unit digits for powers of 7:
We can see that the unit digits repeat in a cycle: 7, 9, 3, 1. The length of this cycle is 4.
To find the unit digit of \(7^{73}\), we need to determine where in this cycle the 73rd power falls. We can do this by dividing the exponent (73) by the length of the cycle (4) and looking at the remainder.
Divide 73 by 4:
$\( \frac{73}{4} $\)
We perform the division:
$\( 73 = 4 \times 18 + 1 $\)
The quotient is 18, and the remainder is 1.
The remainder tells us which position in the cycle the unit digit corresponds to:
Since the remainder when 73 is divided by 4 is 1, the unit digit of \(7^{73}\) is the same as the unit digit of \(7^1\), which is 7.
| Power of 7 | Result | Unit Digit | Position in Cycle (Remainder when exponent / 4) |
|---|---|---|---|
| \(7^1\) | 7 | 7 | 1 (73 mod 4 = 1) |
| \(7^2\) | 49 | 9 | 2 |
| \(7^3\) | 343 | 3 | 3 |
| \(7^4\) | 2401 | 1 | 4 or 0 |
The unit digits of powers of any integer repeat in a cycle. The length of this cycle depends on the unit digit of the base number.
This concept of cyclicity helps quickly determine the unit digit of large powers without calculating the full number.
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