The question asks for the square root of 6561, denoted mathematically as $\sqrt{6561}$. We need to find a number which, when multiplied by itself, yields 6561.
The square root of 6561 is 81.
If (584)2 = 341056, then the value of square root of 34.1056 is:
The sum of the squares of two positive integers is 306. If the square of the larger integer is 25 times the smaller integer, then the difference between the two integers is
The least number which is a perfect square and is divisible by each of the numbers 4, 10 and 12 is :
The addition of the squares of two numbers in squares is 221. What are those numbers?
Find the value of \(\sqrt{9604} \).