All Exams Test series for 1 year @ ₹349 only
Question

What is the power factor for a purely inductive or purely capacitive AC circuit?

The correct answer is

0

In an AC circuit, power factor (PF) is defined as the cosine of the phase angle (ϕ) between the current and voltage. It is represented as:

PF = cos(ϕ)

1. In purely inductive or purely capacitive circuits, the phase difference between current and voltage is 90 degrees because:

  • In a purely inductive circuit, voltage leads the current by 90°.
  • In a purely capacitive circuit, current leads the voltage by 90°.

2. For a 90-degree phase difference, the cosine value is:

cos(90°) = 0

3. Therefore, the power factor for both purely inductive and purely capacitive circuits is:

0

Thus, the correct answer is 0.

Was this answer helpful?

Important Questions from Power in Electric Circuits

  1. Two electric bulbs marked 25 W - 220 V and 100 W - 220 V are connected in series with 440 V supply. Which of the bulb will fuse?

  2. Two electric bulbs are rated '$220$ V, $100$ W' and '$220$ V, $50$ W' respectively.
    If these two bulbs are connected in series across a $220$ V supply, what will be the power consumed by the $100$ W bulb?
  3. Three identical bulbs are connected in parallel to a battery of 6 V. If the current in the circuit is 0.6 A, the power dissipated by the battery is:
  4. An 8 Ω resistor generates 200 J of heat every second. What is the potential difference across the resistor?
  5. Two incandescent bulbs are rated at $P_1 = 200\,\text{W}$ and $P_2 = 100\,\text{W}$, respectively, when operated at a voltage of $V_{rated} = 220\,\text{V}$. If these two bulbs are connected in series across a $V_{supply} = 110\,\text{V}$ DC power supply, determine which bulb will glow brighter and by what factor compared to the other bulb.
Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App