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Question

What is the power factor for a purely inductive or purely capacitive AC circuit?

The correct answer is

0

In an AC circuit, power factor (PF) is defined as the cosine of the phase angle (ϕ) between the current and voltage. It is represented as:

PF = cos(ϕ)

1. In purely inductive or purely capacitive circuits, the phase difference between current and voltage is 90 degrees because:

  • In a purely inductive circuit, voltage leads the current by 90°.
  • In a purely capacitive circuit, current leads the voltage by 90°.

2. For a 90-degree phase difference, the cosine value is:

cos(90°) = 0

3. Therefore, the power factor for both purely inductive and purely capacitive circuits is:

0

Thus, the correct answer is 0.

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Important Questions from Power in Electric Circuits

  1. An electric bulb is connected to a 200 V generator. The current drawn by the bulb is 0.1 A. What is the power of the bulb?

  2. Convert $1 \text{ MWh}$ (megawatt-hour) into Joules.

  3. Two incandescent bulbs are rated at $P_1 = 200\,\text{W}$ and $P_2 = 100\,\text{W}$, respectively, when operated at a voltage of $V_{rated} = 220\,\text{V}$. If these two bulbs are connected in series across a $V_{supply} = 110\,\text{V}$ DC power supply, determine which bulb will glow brighter and by what factor compared to the other bulb.
  4. Two electric bulbs are rated '$220$ V, $100$ W' and '$220$ V, $50$ W' respectively.
    If these two bulbs are connected in series across a $220$ V supply, what will be the power consumed by the $100$ W bulb?
  5. The charge flowing through a resistance $R$ varies with time $t$ as $Q = At^2 - Bt^3$, where $A$ and $B$ are positive constants. The total heat produced in $R$ until the current becomes zero is:
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