What is the mean deviation from the mean of the numbers 10, 9, 21, 16, 24 ?
5.2
The mean deviation from the mean is a measure of dispersion that tells us how spread out the numbers in a dataset are, on average, from their mean. It is calculated as the average of the absolute differences between each number in the dataset and the mean of the dataset.
Mean deviation provides a straightforward way to understand the typical distance of data points from the central value (the mean). It uses absolute values of deviations to avoid positive and negative differences cancelling each other out.
The given numbers are 10, 9, 21, 16, 24.
Let's follow the steps to find the mean deviation from the mean for these numbers.
Step 1: Calculate the Mean (\(\bar{x}\))
The mean is the sum of all numbers divided by the count of numbers.
Number of observations (\(n\)) = 5
Sum of numbers (\(\Sigma x_i\)) = 10 + 9 + 21 + 16 + 24 = 80
Mean (\(\bar{x}\)) = \(\frac{\Sigma x_i}{n} = \frac{80}{5} = 16\)
The mean of the numbers is 16.
Step 2: Find the Absolute Deviations from the Mean
Now, we find the absolute difference between each number and the mean (16).
| Number (\(x_i\)) | Mean (\(\bar{x}\)) | Difference (\(x_i - \bar{x}\)) | Absolute Difference (\(|x_i - \bar{x}|\)) |
|---|---|---|---|
| 10 | 16 | 10 - 16 = -6 | |-6| = 6 |
| 9 | 16 | 9 - 16 = -7 | |-7| = 7 |
| 21 | 16 | 21 - 16 = 5 | |5| = 5 |
| 16 | 16 | 16 - 16 = 0 | |0| = 0 |
| 24 | 16 | 24 - 16 = 8 | |8| = 8 |
The sum of the absolute differences (\(\Sigma |x_i - \bar{x}|\)) = 6 + 7 + 5 + 0 + 8 = 26.
Step 3: Calculate the Mean Deviation from the Mean
The mean deviation is the average of the absolute differences.
Mean Deviation = \(\frac{\Sigma |x_i - \bar{x}|}{n} = \frac{26}{5}\)
Mean Deviation = 5.2
The mean deviation from the mean of the given numbers is 5.2.
| Concept | Description | Formula (from Mean) |
|---|---|---|
| Mean (\(\bar{x}\)) | Average of the dataset. | \(\bar{x} = \frac{\Sigma x_i}{n}\) |
| Deviation | Difference between a data point and the mean. | \(x_i - \bar{x}\) |
| Absolute Deviation | Positive value of the difference. | \(|x_i - \bar{x}|\) |
| Mean Deviation | Average of the absolute deviations. | MD = \(\frac{\Sigma |x_i - \bar{x}|}{n}\) |
Mean deviation is one type of measure of dispersion. Measures of dispersion quantify how spread out the data points are. Other common measures include:
Each measure of dispersion provides a different perspective on the spread of the data. Mean deviation is easy to understand but is less frequently used in inferential statistics compared to standard deviation because it uses absolute values, which are mathematically harder to handle in further calculations.
What is the mean deviation about the mean ?
What is the coefficient of mean deviation of 21, 34, 23, 39, 26, 37, 40, 20, 33, 27 (taken from mean)?
What is the mean deviation of first 10 even natural numbers?
The sum of deviations of n number of observations measured from 2.5 is 50. The sum of deviations of the same set of observations measured from 3.5 is -50. What is the value of n?
What is the mean deviation about the mean ?
Let xi, i = 1, 2, ..., n be n observations and wi = pxi + k, i = 1, 2, ..., n where p and k are constants. If the mean of xi's is 48 and standard deviation is 12, whereas the mean of wi's is 55 and standard deviation is 15, then the value of p and k should be
If the mean deviation 1, 1 + d, 1 + 2d, ..., 1 + 100d from their mean is 255, then d is equal to
The mean of 5 observation is 5 and their variance is 124. If three of the observations are 1, 2, 6, then the mean deviation from the mean of the data is