All Exams Test series for 1 year @ ₹349 only
Question

What is the largest number which divides both 235 - 1 and 291 - 1 ?

This question was previously asked in
CDS I 2023 English Previous Year Paper (16-April-2023)
The correct answer is

127

Finding the Largest Number Dividing Powers of Two

The question asks for the largest number that divides both \(2^{35} - 1\) and \(2^{91} - 1\). This is the definition of the Greatest Common Divisor (GCD) of these two numbers. So, we need to find \(\text{gcd}(2^{35} - 1, 2^{91} - 1)\).

There is a useful property concerning the GCD of numbers of the form \(2^a - 1\) and \(2^b - 1\). The property states that:

\(\text{gcd}(2^a - 1, 2^b - 1) = 2^{\text{gcd}(a, b)} - 1\)

In this problem, \(a = 35\) and \(b = 91\). Applying the property, we need to find \(\text{gcd}(35, 91)\) first.

Calculating the Greatest Common Divisor of 35 and 91

We can find the GCD of 35 and 91 by listing their factors or by using prime factorization.

Method 1: Prime Factorization

  • Prime factors of 35: \(35 = 5 \times 7\).
  • Prime factors of 91: \(91 = 7 \times 13\).

The common prime factor is 7. Therefore, \(\text{gcd}(35, 91) = 7\).

Method 2: Euclidean Algorithm

We can use the Euclidean algorithm to find the GCD of 35 and 91:

  • Divide 91 by 35: \(91 = 2 \times 35 + 21\)
  • Divide 35 by the remainder 21: \(35 = 1 \times 21 + 14\)
  • Divide 21 by the remainder 14: \(21 = 1 \times 14 + 7\)
  • Divide 14 by the remainder 7: \(14 = 2 \times 7 + 0\)

The last non-zero remainder is 7. Therefore, \(\text{gcd}(35, 91) = 7\).

Both methods show that \(\text{gcd}(35, 91) = 7\).

Applying the GCD Property

Now we can use the property \(\text{gcd}(2^a - 1, 2^b - 1) = 2^{\text{gcd}(a, b)} - 1\) with \(a=35\), \(b=91\), and \(\text{gcd}(35, 91) = 7\).

\(\text{gcd}(2^{35} - 1, 2^{91} - 1) = 2^{\text{gcd}(35, 91)} - 1 = 2^7 - 1\)

Calculating the Final Value

Finally, we calculate the value of \(2^7 - 1\):

  • \(2^1 = 2\)
  • \(2^2 = 4\)
  • \(2^3 = 8\)
  • \(2^4 = 16\)
  • \(2^5 = 32\)
  • \(2^6 = 64\)
  • \(2^7 = 128\)

So, \(2^7 - 1 = 128 - 1 = 127\).

The largest number that divides both \(2^{35} - 1\) and \(2^{91} - 1\) is 127.

Revision Table: Key Concepts

Concept Explanation Application Here
Greatest Common Divisor (GCD) The largest positive integer that divides two or more integers without leaving a remainder. Finding \(\text{gcd}(2^{35} - 1, 2^{91} - 1)\).
GCD of \(2^a-1\) and \(2^b-1\) Property: \(\text{gcd}(2^a - 1, 2^b - 1) = 2^{\text{gcd}(a, b)} - 1\). Reduces the problem to finding \(\text{gcd}(35, 91)\).
Prime Factorization Breaking down a number into its prime factors. Used to find \(\text{gcd}(35, 91) = 7\).
Euclidean Algorithm An efficient method for computing the GCD of two integers. Also used to find \(\text{gcd}(35, 91) = 7\).

Additional Information: Properties of Powers and GCD

The property \(\text{gcd}(2^a - 1, 2^b - 1) = 2^{\text{gcd}(a, b)} - 1\) is a specific case of a more general property for integers \(x > 1\): \(\text{gcd}(x^a - 1, x^b - 1) = x^{\text{gcd}(a, b)} - 1\). This property is very useful in number theory problems involving exponents.

The Euclidean algorithm is a fundamental algorithm in number theory. It is based on the principle that the GCD of two numbers does not change if the larger number is replaced by its difference with the smaller number, or more efficiently, by its remainder when divided by the smaller number.

Understanding GCD and its properties, especially with exponents, helps solve various problems in number theory and competitive mathematics.

Was this answer helpful?

Similar Questions

  1. If 17 2020 is divided by 18, then what is the remainder ?

  2. What is the remainder when 27 27 - 15 27 is divided by 6?

  3. There is a remainder of 4 when a number is divided by 7.what will be the remainder. if the square of the same number is divided by 7?

  4. If the number 413283P759387 is divisible by 13, then what is the value of P?

  5. A number divides 12288, 28200 and 44333 so as to leave the same remainder in each case. What is that number?

  6. If 10 ndivides 6 23 × 75 9× 105 2, then what is the largest value of n?

  7. 710 − 510  is divisible by

  8. A is a set of positive integers such that when divided by 2, 3, 4, 5 and 6 leaves the reminder 1, 2, 3, 4 and 5 respectively. How many integers between 0 and 100 belong to the set A?

  9. 4 61 + 4 62  + 4 63  + 4 64  is divisible by

  10. Let p = 2 2n + 2 + m and q = 2 4n  - m (where n is even natural number). What should be the least value of m such that p as well as q is divisible by 5?


Important Questions from Divisibility and Remainder

  1. If the 8-digit number 888x53y4 is divisible by 72, then what is the value of (7x + 2y), for the maximum value of y?

  2. If all positive divisors of 132 are arranged in descending order, then what digit will be at unit place of first divisor ?

  3. If 3 2019 is divided by 10, then what is the remainder?

  4. The number 3798125P369 is divisible by 7. What is the value of the digit P?

  5. Consider all 3-digit numbers (without repetition of digits) obtained using three non-zero digits which are multiples of 3. Let S be their sum.

    Which of the following is/are correct?

    1. S is always divisible by 74.

    2. S is always divisible by 9.

    select the correct answer using the code given below:

Need Expert Advice?
Test Series
CDS img
Defence
UPSC CDS 2026 Mock Test Series
536 Tests 4 Tests Free
1647 Attempts
4.3(174)
English, Hindi
More Questions from CDS

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App