All Exams Test series for 1 year @ ₹349 only
Question

What is the largest number which divides both 235 - 1 and 291 - 1 ?

This question was previously asked in
CDS I 2023 English Previous Year Paper (16-April-2023)
The correct answer is

127

Finding the Largest Number Dividing Powers of Two

The question asks for the largest number that divides both \(2^{35} - 1\) and \(2^{91} - 1\). This is the definition of the Greatest Common Divisor (GCD) of these two numbers. So, we need to find \(\text{gcd}(2^{35} - 1, 2^{91} - 1)\).

There is a useful property concerning the GCD of numbers of the form \(2^a - 1\) and \(2^b - 1\). The property states that:

\(\text{gcd}(2^a - 1, 2^b - 1) = 2^{\text{gcd}(a, b)} - 1\)

In this problem, \(a = 35\) and \(b = 91\). Applying the property, we need to find \(\text{gcd}(35, 91)\) first.

Calculating the Greatest Common Divisor of 35 and 91

We can find the GCD of 35 and 91 by listing their factors or by using prime factorization.

Method 1: Prime Factorization

  • Prime factors of 35: \(35 = 5 \times 7\).
  • Prime factors of 91: \(91 = 7 \times 13\).

The common prime factor is 7. Therefore, \(\text{gcd}(35, 91) = 7\).

Method 2: Euclidean Algorithm

We can use the Euclidean algorithm to find the GCD of 35 and 91:

  • Divide 91 by 35: \(91 = 2 \times 35 + 21\)
  • Divide 35 by the remainder 21: \(35 = 1 \times 21 + 14\)
  • Divide 21 by the remainder 14: \(21 = 1 \times 14 + 7\)
  • Divide 14 by the remainder 7: \(14 = 2 \times 7 + 0\)

The last non-zero remainder is 7. Therefore, \(\text{gcd}(35, 91) = 7\).

Both methods show that \(\text{gcd}(35, 91) = 7\).

Applying the GCD Property

Now we can use the property \(\text{gcd}(2^a - 1, 2^b - 1) = 2^{\text{gcd}(a, b)} - 1\) with \(a=35\), \(b=91\), and \(\text{gcd}(35, 91) = 7\).

\(\text{gcd}(2^{35} - 1, 2^{91} - 1) = 2^{\text{gcd}(35, 91)} - 1 = 2^7 - 1\)

Calculating the Final Value

Finally, we calculate the value of \(2^7 - 1\):

  • \(2^1 = 2\)
  • \(2^2 = 4\)
  • \(2^3 = 8\)
  • \(2^4 = 16\)
  • \(2^5 = 32\)
  • \(2^6 = 64\)
  • \(2^7 = 128\)

So, \(2^7 - 1 = 128 - 1 = 127\).

The largest number that divides both \(2^{35} - 1\) and \(2^{91} - 1\) is 127.

Revision Table: Key Concepts

Concept Explanation Application Here
Greatest Common Divisor (GCD) The largest positive integer that divides two or more integers without leaving a remainder. Finding \(\text{gcd}(2^{35} - 1, 2^{91} - 1)\).
GCD of \(2^a-1\) and \(2^b-1\) Property: \(\text{gcd}(2^a - 1, 2^b - 1) = 2^{\text{gcd}(a, b)} - 1\). Reduces the problem to finding \(\text{gcd}(35, 91)\).
Prime Factorization Breaking down a number into its prime factors. Used to find \(\text{gcd}(35, 91) = 7\).
Euclidean Algorithm An efficient method for computing the GCD of two integers. Also used to find \(\text{gcd}(35, 91) = 7\).

Additional Information: Properties of Powers and GCD

The property \(\text{gcd}(2^a - 1, 2^b - 1) = 2^{\text{gcd}(a, b)} - 1\) is a specific case of a more general property for integers \(x > 1\): \(\text{gcd}(x^a - 1, x^b - 1) = x^{\text{gcd}(a, b)} - 1\). This property is very useful in number theory problems involving exponents.

The Euclidean algorithm is a fundamental algorithm in number theory. It is based on the principle that the GCD of two numbers does not change if the larger number is replaced by its difference with the smaller number, or more efficiently, by its remainder when divided by the smaller number.

Understanding GCD and its properties, especially with exponents, helps solve various problems in number theory and competitive mathematics.

Was this answer helpful?

Similar Questions

  1. What is the remainder when the sum 1 5+ 2 5+ 3 5+ 4 5+ 5 5is divided by 4 ?

  2. If the number 23P62971335 is divisible by the smallest odd composite number, then what is the value of P ?

  3. x3 +  x 2 + 16 is exactly divisible by x, where x is a positive integer. The number of all such possible values of x is 

  4. 4x 3 + 12x 2 - x - 3 is divisible by

  5. What is the remainder when 6599 is divided by 11 ?  

  6. When every even power of every odd integer (greater than 1) is divided by 8, what is the remainder ?  

  7. Consider a 6-digit number of the form XYXYXY. The number is divisible by :  

  8. What is the remainder when 27 27 - 15 27 is divided by 6?

  9. If the number 413283P759387 is divisible by 13, then what is the value of P?

  10. If 10 ndivides 6 23 × 75 9× 105 2, then what is the largest value of n?


Important Questions from Divisibility and Remainder

  1. If all positive divisors of 132 are arranged in descending order, then what digit will be at unit place of first divisor ?

  2. If 3 2019 is divided by 10, then what is the remainder?

  3. The number 3798125P369 is divisible by 7. What is the value of the digit P?

  4. Consider all 3-digit numbers (without repetition of digits) obtained using three non-zero digits which are multiples of 3. Let S be their sum.

    Which of the following is/are correct?

    1. S is always divisible by 74.

    2. S is always divisible by 9.

    select the correct answer using the code given below:

  5. How many 3-digit natural numbers (without repetition of digits) are there such that each digit is odd and the number is divisible by 5?

Need Expert Advice?
Test Series
CDS img
Defence
UPSC CDS 2026 Mock Test Series
559 Tests 4 Tests Free
1778 Attempts
4.3(192)
English, Hindi
More Questions from CDS

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App