What is the ionization constant of formic acid (HCOOH)?
\(1.8 \times 10^{-4}\)
Formic acid (methanoic acid) is a weak carboxylic acid that ionizes only partially in water: HCOOH ⇌ HCOO⁻ + H⁺.
Its acid dissociation constant is \(K_a = \frac{[HCOO^-][H^+]}{[HCOOH]}\), which has a value of about \(1.8 \times 10^{-4}\) at 25 °C (pKa ≈ 3.75).
This makes formic acid roughly ten times stronger than acetic acid, whose \(K_a\) is about \(1.8 \times 10^{-5}\).
Hence, \(1.8 \times 10^{-4}\).
What is the ionization constant of acetic acid (\(CH_3COOH\))?
What is the pH of a solution prepared by dissolving $0.0025$ moles of $HNO_3$ in $250\,mL$ of water?
Which species acts as acid like behaviour in the following reaction?
\(HPO_4^{2-}+NH_4^{1+}\rightarrow H_2PO_4^{1-}+NH_3\)
Aqueous solution of CH 3COONa is:
pH of a neutral solution is ___________.
For the reaction N 2(g) + 3H 2(g) \(\rightleftharpoons\) 2NH 3(g) ΔH = -ve :