What is the eccentricity \((e)\) of the parabola \(4x^2 + y = 0\)?
\(e=1\)
The equation \(4x^2+y=0\), i.e. \(x^2=-\dfrac{y}{4}\), represents a parabola. By definition, every parabola has eccentricity exactly equal to \(1\), regardless of the specific coefficients in its equation, so \(e=1\).
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