This solution explains how to find the compound ratio for the given set of ratios: $45 : 75$, $3 : 5$, $51 : 68$, and $256 : 81$. The compound ratio is calculated by multiplying the first terms together and the second terms together.
The compound ratio of several ratios $a : b$, $c : d$, $e : f$, ... is given by $(a \times c \times e \times ...) : (b \times d \times f \times ...)$.
Simplify individual ratios:
Multiply the simplified ratios:
Compound Ratio = $\frac{3}{5} \times \frac{3}{5} \times \frac{3}{4} \times \frac{256}{81}$
Calculate the product of numerators and denominators:
Numerator Product = $3 \times 3 \times 3 \times 256 = 27 \times 256$
Denominator Product = $5 \times 5 \times 4 \times 81 = 25 \times 4 \times 81 = 100 \times 81 = 8100$
Compound Ratio = $\frac{27 \times 256}{8100}$
Simplify the resulting fraction:
Divide numerator and denominator by common factors.
Notice that $81 = 3 \times 27$. So, $\frac{27}{8100} = \frac{1}{3 \times 100} = \frac{1}{300}$.
The ratio becomes $\frac{1 \times 256}{300} = \frac{256}{300}$.
Simplify $\frac{256}{300}$ by dividing both by 4:
$\frac{256 \div 4}{300 \div 4} = \frac{64}{75}$.
The compound ratio is $\frac{64}{75}$. This corresponds to Option A.
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