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Question

What is the compound ratio of $45 : 75$, $3 : 5$, $51 : 68$ and $256 : 81$?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
$\frac{64}{75}$

Compound Ratio Calculation

This solution explains how to find the compound ratio for the given set of ratios: $45 : 75$, $3 : 5$, $51 : 68$, and $256 : 81$. The compound ratio is calculated by multiplying the first terms together and the second terms together.

Compound Ratio Definition

The compound ratio of several ratios $a : b$, $c : d$, $e : f$, ... is given by $(a \times c \times e \times ...) : (b \times d \times f \times ...)$.

Ratio Calculation Steps

  1. Simplify individual ratios:

    • $45 : 75$ simplifies to $\frac{45}{75} = \frac{3 \times 15}{5 \times 15} = \frac{3}{5}$.
    • $3 : 5$ is already in simplest form, $\frac{3}{5}$.
    • $51 : 68$ simplifies to $\frac{51}{68} = \frac{3 \times 17}{4 \times 17} = \frac{3}{4}$.
    • $256 : 81$ is $\frac{256}{81}$.
  2. Multiply the simplified ratios:

    Compound Ratio = $\frac{3}{5} \times \frac{3}{5} \times \frac{3}{4} \times \frac{256}{81}$

  3. Calculate the product of numerators and denominators:

    Numerator Product = $3 \times 3 \times 3 \times 256 = 27 \times 256$

    Denominator Product = $5 \times 5 \times 4 \times 81 = 25 \times 4 \times 81 = 100 \times 81 = 8100$

    Compound Ratio = $\frac{27 \times 256}{8100}$

  4. Simplify the resulting fraction:

    Divide numerator and denominator by common factors.

    Notice that $81 = 3 \times 27$. So, $\frac{27}{8100} = \frac{1}{3 \times 100} = \frac{1}{300}$.

    The ratio becomes $\frac{1 \times 256}{300} = \frac{256}{300}$.

    Simplify $\frac{256}{300}$ by dividing both by 4:

    $\frac{256 \div 4}{300 \div 4} = \frac{64}{75}$.

Resulting Compound Ratio

The compound ratio is $\frac{64}{75}$. This corresponds to Option A.

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Similar Questions

  1. The following ratios are given:

    \(a : b = 2 : 3\)

    \(b : c = 4 : 5\)

    \(c : d = 3 : 2\)

    \(d : e = 5 : 4\)

    What is the value of the ratio a : e?

  2. If \(a:b = 12:13\) and \(b:c = 4:5\), what is \(a:c\)?


Important Questions from Compound Ratios

  1. The train fare, bus fare and air fare between 2 places are in the ratio 5 : 8 : 12, the number of passenger travelled by them is in the ratio 3 : 4 : 5 and the total fare collected on a particular day for these modes of transportation for a single trip is Rs. 1,07,000. Find the fare collected from the air passengers.

  2. The compounded ratio of (1 ∶ 3), (6 ∶ 5) and (7 ∶10) is:

  3. Rs. 750 are divided among A, B and C in such a manner that A : B = 5 : 2 and B : C = 7 : 13, What is A’s share?

  4. Rs. 750 are divided among A, B and C in such a manner that A : B = 5 : 2 and B : C = 7 : 13, What is B’s share?

  5. Two numbers are in the ratio 3 : 5. If 4 is subtracted from each of these two numbers, the new numbers then are in the ratio 4 : 7. Find the smaller of the two original numbers.

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