Consider the following data for the next three (03) items that follow : There are 90 applicants for a job. Some of them are graduates. Some of them have less than three years experience. Let G be the event that the first applicant interviewed is a graduate and T be the event that first applicant interviewed has at least 3 years experience.Number of graduates Number of non-graduates At least 3 years experience 18 9 Less than 3 years experience 36 27
What is \(P(\overline T | \overline G)\) equal to?
The problem provides data about 90 applicants for a job, categorized by their graduate status and years of experience. We are asked to calculate a specific conditional probability based on this data. Let's first organize the given information in a clear table.
| Category | At least 3 years experience (T) | Less than 3 years experience (\(\overline T\)) | Total |
|---|---|---|---|
| Graduates (G) | 18 | 36 | 18 + 36 = 54 |
| Non-graduates (\(\overline G\)) | 9 | 27 | 9 + 27 = 36 |
| Total | 18 + 9 = 27 | 36 + 27 = 63 | 27 + 63 = 90 |
We are given the following events:
The question asks for \(P(\overline T | \overline G)\), which is the probability that the first applicant interviewed has less than 3 years experience, given that they are a non-graduate. The notation \(\overline G\) means the applicant is not a graduate (i.e., a non-graduate), and \(\overline T\) means the applicant does not have at least 3 years experience (i.e., has less than 3 years experience).
Conditional probability \(P(A|B)\) is the probability of event A occurring given that event B has already occurred. It is calculated using the formula:
\(P(A|B) = \frac{P(A \cap B)}{P(B)}\)
In our case, \(A = \overline T\) and \(B = \overline G\). So, we need to calculate \(P(\overline T | \overline G) = \frac{P(\overline T \cap \overline G)}{P(\overline G)}\).
Alternatively, for problems involving selecting one item from a group, the conditional probability \(P(A|B)\) can be calculated directly as the ratio of the number of outcomes where both A and B occur to the number of outcomes where B occurs:
\(P(A|B) = \frac{\text{Number of outcomes in } A \cap B}{\text{Number of outcomes in } B}\)
Let's use the direct method based on the counts from the table.
Now, we can calculate the conditional probability:
\(P(\overline T | \overline G) = \frac{\text{Number of non-graduates with less than 3 years experience}}{\text{Total number of non-graduates}}\)
\(P(\overline T | \overline G) = \frac{27}{36}\)
We can simplify the fraction \(\frac{27}{36}\) by dividing both the numerator and the denominator by their greatest common divisor, which is 9.
\(\frac{27 \div 9}{36 \div 9} = \frac{3}{4}\)
Therefore, \(P(\overline T | \overline G)\) is equal to \(\frac{3}{4}\).
The probability that the first applicant interviewed has less than 3 years experience, given that they are a non-graduate, is \(\frac{3}{4}\).
Let's quickly summarize some related total probabilities from the table for revision.
We calculated \(P(\overline T | \overline G) = \frac{P(\overline T \cap \overline G)}{P(\overline G)} = \frac{27/90}{36/90} = \frac{27}{36} = \frac{3}{4}\), which matches our direct calculation.
Conditional probability is a fundamental concept in probability theory. It helps us understand how the probability of an event changes when we know that another event has occurred. The formula \(P(A|B) = \frac{P(A \cap B)}{P(B)}\) is key, provided \(P(B) \gt 0\). In simpler terms for discrete events, it's the proportion of times A occurs within the instances where B occurs.
It's different from \(P(A \cap B)\), which is the probability that both A and B happen together out of the entire sample space. Conditional probability shrinks the sample space to just the outcomes of event B.
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