Consider the following data for the next three (03) items that follow : There are 90 applicants for a job. Some of them are graduates. Some of them have less than three years experience. Let G be the event that the first applicant interviewed is a graduate and T be the event that first applicant interviewed has at least 3 years experience.Number of graduates Number of non-graduates At least 3 years experience 18 9 Less than 3 years experience 36 27
What is \(P(G | \overline T) \) equal to?
The problem asks us to calculate the conditional probability \(P(G | \overline T)\), which represents the probability that the first applicant interviewed is a graduate (\(G\)), given that the first applicant interviewed has less than three years of experience (\(\overline T\)). We are provided with data on 90 applicants categorized by their graduate status and years of experience.
Let's first organize the given data in a table:
| At least 3 years experience (T) | Less than 3 years experience (\(\overline T\)) | Total | |
|---|---|---|---|
| Number of graduates (G) | 18 | 36 | 54 |
| Number of non-graduates (\(\overline G\)) | 9 | 27 | 36 |
| Total | 27 | 63 | 90 |
From the table, we can identify the number of applicants in different categories:
The formula for the conditional probability of event A occurring given that event B has occurred is:
\(P(A | B) = \frac{P(A \cap B)}{P(B)}\)
In our case, we want to find \(P(G | \overline T)\). This means we need to find the probability that an applicant is a graduate (\(G\)) given that they have less than 3 years experience (\(\overline T\)). Using the formula, we have:
\(P(G | \overline T) = \frac{P(G \cap \overline T)}{P(\overline T)}\)
First, let's find \(P(G \cap \overline T)\). This is the probability that an applicant is a graduate AND has less than 3 years experience. From the table, the number of applicants who are graduates and have less than 3 years experience is 36. The total number of applicants is 90.
So, \(P(G \cap \overline T) = \frac{\text{Number of graduates with < 3 years experience}}{\text{Total number of applicants}} = \frac{36}{90}\)
Next, let's find \(P(\overline T)\). This is the probability that an applicant has less than 3 years experience. From the table, the total number of applicants with less than 3 years experience is the sum of graduates with less than 3 years experience and non-graduates with less than 3 years experience, which is \(36 + 27 = 63\). The total number of applicants is 90.
So, \(P(\overline T) = \frac{\text{Total number of applicants with < 3 years experience}}{\text{Total number of applicants}} = \frac{63}{90}\)
Now we can substitute these probabilities into the conditional probability formula:
\(P(G | \overline T) = \frac{P(G \cap \overline T)}{P(\overline T)} = \frac{36/90}{63/90}\)
We can cancel out the denominator 90 from both the numerator and the denominator:
\(P(G | \overline T) = \frac{36}{63}\)
To simplify the fraction \(\frac{36}{63}\), we find the greatest common divisor (GCD) of 36 and 63. Both numbers are divisible by 9.
So, the simplified fraction is \(\frac{4}{7}\).
Therefore, \(P(G | \overline T) = \frac{4}{7}\).
The conditional probability \(P(G | \overline T)\), which is the probability that the first applicant interviewed is a graduate given they have less than 3 years experience, is equal to \(\frac{4}{7}\). This calculation is based directly on the data provided in the table for the 90 applicants.
| Concept | Definition | Formula |
|---|---|---|
| Probability of Event A | The likelihood of event A occurring. | \(P(A) = \frac{\text{Number of outcomes in A}}{\text{Total number of outcomes}}\) |
| Joint Probability | The probability of two events A and B both occurring. | \(P(A \cap B)\) |
| Conditional Probability | The probability of event A occurring given that event B has already occurred. | \(P(A | B) = \frac{P(A \cap B)}{P(B)}\) |
| Complement of an Event | The probability of event A not occurring. | \(P(\overline A) = 1 - P(A)\) |
The data presented in the problem is often called a contingency table or cross-tabulation table. These tables are very useful for calculating probabilities involving two categorical variables, like 'graduate status' and 'experience level' in this case. From a contingency table, we can easily calculate:
Understanding how to extract information from a contingency table is key to solving many probability problems, especially those involving conditional probability.
What is \(P(\overline T | \overline G)\) equal to?
What is \(P (G \cap \overline T)\) equal to?
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