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Question

What is cot A + cosec A equal to?

This question was previously asked in
NDA II 2019 GAT Previous Year Paper (17-Nov-2019)
The correct answer is \(\cot \left( \frac{A}{2} \right)\)

Understanding the Trigonometric Expression cot A + cosec A

The question asks us to find an equivalent expression for the sum of cotangent A and cosecant A, represented as \(\cot A + \operatorname{cosec} A\). We need to simplify this expression and match it with one of the given options, which involve half-angle trigonometric functions.

Step-by-Step Simplification

We can start by expressing \(\cot A\) and \(\operatorname{cosec} A\) in terms of sine and cosine functions. The fundamental identities are:

  • \(\cot A = \frac{\cos A}{\sin A}\)
  • \(\operatorname{cosec} A = \frac{1}{\sin A}\)

Now, substitute these into the given expression:

\(\cot A + \operatorname{cosec} A = \frac{\cos A}{\sin A} + \frac{1}{\sin A}\)

Since both terms have a common denominator \(\sin A\), we can combine them:

\(\cot A + \operatorname{cosec} A = \frac{\cos A + 1}{\sin A} = \frac{1 + \cos A}{\sin A}\)

To relate this expression to the half-angle options, we can use trigonometric identities for \(1 + \cos A\) and \(\sin A\) in terms of \(\frac{A}{2}\). The relevant half-angle or double-angle identities (derived from \(\cos(2x) = 2\cos^2 x - 1\) and \(\sin(2x) = 2\sin x \cos x\)) are:

  • \(\cos(2x) = 2\cos^2 x - 1 \implies 1 + \cos(2x) = 2\cos^2 x\). Replacing \(2x\) with \(A\), we get \(1 + \cos A = 2\cos^2 \left( \frac{A}{2} \right)\).
  • \(\sin(2x) = 2\sin x \cos x\). Replacing \(2x\) with \(A\), we get \(\sin A = 2\sin \left( \frac{A}{2} \right) \cos \left( \frac{A}{2} \right)\).

Substitute these identities into the simplified expression \(\frac{1 + \cos A}{\sin A}\):

\(\frac{1 + \cos A}{\sin A} = \frac{2\cos^2 \left( \frac{A}{2} \right)}{2\sin \left( \frac{A}{2} \right) \cos \left( \frac{A}{2} \right)}\)

Now, we can cancel out the common terms from the numerator and the denominator. The constant 2 cancels out, and one term of \(\cos \left( \frac{A}{2} \right)\) cancels out:

\(\frac{2\cos^2 \left( \frac{A}{2} \right)}{2\sin \left( \frac{A}{2} \right) \cos \left( \frac{A}{2} \right)} = \frac{\cos \left( \frac{A}{2} \right)}{\sin \left( \frac{A}{2} \right)}\)

Finally, we recognize that the ratio of cosine to sine is the cotangent function:

\(\frac{\cos \left( \frac{A}{2} \right)}{\sin \left( \frac{A}{2} \right)} = \cot \left( \frac{A}{2} \right)\)

Thus, \(\cot A + \operatorname{cosec} A\) is equal to \(\cot \left( \frac{A}{2} \right)\).

Comparing with Options

Let's compare our simplified expression with the given options:

  • Option 1: \(\tan \left( \frac{A}{2} \right)\)
  • Option 2: \(\cot \left( \frac{A}{2} \right)\)
  • Option 3: \(2\tan \left( \frac{A}{2} \right)\)
  • Option 4: \(2\cot \left( \frac{A}{2} \right)\)

Our derived expression \(\cot \left( \frac{A}{2} \right)\) matches Option 2.

Original Expression Simplification Steps Equivalent Expression
\(\cot A + \operatorname{cosec} A\) Convert to sin and cos, combine fractions \(\frac{1 + \cos A}{\sin A}\)
\(\frac{1 + \cos A}{\sin A}\) Apply half-angle identities for \(1+\cos A\) and \(\sin A\) \(\frac{2\cos^2 \left( \frac{A}{2} \right)}{2\sin \left( \frac{A}{2} \right) \cos \left( \frac{A}{2} \right)}\)
\(\frac{2\cos^2 \left( \frac{A}{2} \right)}{2\sin \left( \frac{A}{2} \right) \cos \left( \frac{A}{2} \right)}\) Cancel common terms \(\frac{\cos \left( \frac{A}{2} \right)}{\sin \left( \frac{A}{2} \right)}\)
\(\frac{\cos \left( \frac{A}{2} \right)}{\sin \left( \frac{A}{2} \right)}\) Recognize as cotangent \(\cot \left( \frac{A}{2} \right)\)

Revision Table: Key Trigonometric Identities

Identity Type Identity
Reciprocal Identity \(\operatorname{cosec} A = \frac{1}{\sin A}\)
Ratio Identity \(\cot A = \frac{\cos A}{\sin A}\)
Double Angle Identity (Cosine) \(\cos(2x) = 2\cos^2 x - 1\)
Derived Identity (Cosine) \(1 + \cos(2x) = 2\cos^2 x\)
Half Angle Identity (Cosine) \(1 + \cos A = 2\cos^2 \left( \frac{A}{2} \right)\)
Double Angle Identity (Sine) \(\sin(2x) = 2\sin x \cos x\)
Half Angle Identity (Sine) \(\sin A = 2\sin \left( \frac{A}{2} \right) \cos \left( \frac{A}{2} \right)\)
Ratio Identity \(\cot x = \frac{\cos x}{\sin x}\)

Additional Information on Trigonometric Simplification

Simplifying trigonometric expressions often involves converting functions to their sine and cosine forms, finding common denominators, and applying fundamental identities like Pythagorean identities, sum/difference formulas, double angle formulas, or half-angle formulas. Recognizing patterns and knowing these identities is crucial for simplifying complex expressions and solving trigonometric equations. The expression \(\cot A + \operatorname{cosec} A\) is a common one that simplifies neatly using half-angle identities. Another related expression is \(\tan A + \sec A\), which simplifies to \(\tan \left( \frac{\pi}{4} + \frac{A}{2} \right)\).

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