What is cot A + cosec A equal to?
The question asks us to find an equivalent expression for the sum of cotangent A and cosecant A, represented as \(\cot A + \operatorname{cosec} A\). We need to simplify this expression and match it with one of the given options, which involve half-angle trigonometric functions.
We can start by expressing \(\cot A\) and \(\operatorname{cosec} A\) in terms of sine and cosine functions. The fundamental identities are:
Now, substitute these into the given expression:
\(\cot A + \operatorname{cosec} A = \frac{\cos A}{\sin A} + \frac{1}{\sin A}\)
Since both terms have a common denominator \(\sin A\), we can combine them:
\(\cot A + \operatorname{cosec} A = \frac{\cos A + 1}{\sin A} = \frac{1 + \cos A}{\sin A}\)
To relate this expression to the half-angle options, we can use trigonometric identities for \(1 + \cos A\) and \(\sin A\) in terms of \(\frac{A}{2}\). The relevant half-angle or double-angle identities (derived from \(\cos(2x) = 2\cos^2 x - 1\) and \(\sin(2x) = 2\sin x \cos x\)) are:
Substitute these identities into the simplified expression \(\frac{1 + \cos A}{\sin A}\):
\(\frac{1 + \cos A}{\sin A} = \frac{2\cos^2 \left( \frac{A}{2} \right)}{2\sin \left( \frac{A}{2} \right) \cos \left( \frac{A}{2} \right)}\)
Now, we can cancel out the common terms from the numerator and the denominator. The constant 2 cancels out, and one term of \(\cos \left( \frac{A}{2} \right)\) cancels out:
\(\frac{2\cos^2 \left( \frac{A}{2} \right)}{2\sin \left( \frac{A}{2} \right) \cos \left( \frac{A}{2} \right)} = \frac{\cos \left( \frac{A}{2} \right)}{\sin \left( \frac{A}{2} \right)}\)
Finally, we recognize that the ratio of cosine to sine is the cotangent function:
\(\frac{\cos \left( \frac{A}{2} \right)}{\sin \left( \frac{A}{2} \right)} = \cot \left( \frac{A}{2} \right)\)
Thus, \(\cot A + \operatorname{cosec} A\) is equal to \(\cot \left( \frac{A}{2} \right)\).
Let's compare our simplified expression with the given options:
Our derived expression \(\cot \left( \frac{A}{2} \right)\) matches Option 2.
| Original Expression | Simplification Steps | Equivalent Expression |
|---|---|---|
| \(\cot A + \operatorname{cosec} A\) | Convert to sin and cos, combine fractions | \(\frac{1 + \cos A}{\sin A}\) |
| \(\frac{1 + \cos A}{\sin A}\) | Apply half-angle identities for \(1+\cos A\) and \(\sin A\) | \(\frac{2\cos^2 \left( \frac{A}{2} \right)}{2\sin \left( \frac{A}{2} \right) \cos \left( \frac{A}{2} \right)}\) |
| \(\frac{2\cos^2 \left( \frac{A}{2} \right)}{2\sin \left( \frac{A}{2} \right) \cos \left( \frac{A}{2} \right)}\) | Cancel common terms | \(\frac{\cos \left( \frac{A}{2} \right)}{\sin \left( \frac{A}{2} \right)}\) |
| \(\frac{\cos \left( \frac{A}{2} \right)}{\sin \left( \frac{A}{2} \right)}\) | Recognize as cotangent | \(\cot \left( \frac{A}{2} \right)\) |
| Identity Type | Identity |
|---|---|
| Reciprocal Identity | \(\operatorname{cosec} A = \frac{1}{\sin A}\) |
| Ratio Identity | \(\cot A = \frac{\cos A}{\sin A}\) |
| Double Angle Identity (Cosine) | \(\cos(2x) = 2\cos^2 x - 1\) |
| Derived Identity (Cosine) | \(1 + \cos(2x) = 2\cos^2 x\) |
| Half Angle Identity (Cosine) | \(1 + \cos A = 2\cos^2 \left( \frac{A}{2} \right)\) |
| Double Angle Identity (Sine) | \(\sin(2x) = 2\sin x \cos x\) |
| Half Angle Identity (Sine) | \(\sin A = 2\sin \left( \frac{A}{2} \right) \cos \left( \frac{A}{2} \right)\) |
| Ratio Identity | \(\cot x = \frac{\cos x}{\sin x}\) |
Simplifying trigonometric expressions often involves converting functions to their sine and cosine forms, finding common denominators, and applying fundamental identities like Pythagorean identities, sum/difference formulas, double angle formulas, or half-angle formulas. Recognizing patterns and knowing these identities is crucial for simplifying complex expressions and solving trigonometric equations. The expression \(\cot A + \operatorname{cosec} A\) is a common one that simplifies neatly using half-angle identities. Another related expression is \(\tan A + \sec A\), which simplifies to \(\tan \left( \frac{\pi}{4} + \frac{A}{2} \right)\).
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