What happens to the kinetic energy of a moving object if its velocity is tripled?
It becomes 9 times
It becomes 9 times is correct.
The kinetic energy of a body of mass \(m\) moving with velocity \(v\) is \(KE = \dfrac{1}{2}mv^2\), so kinetic energy varies as the square of velocity.
Let the new velocity be \(v' = 3v\) with the same mass.
Then \(KE' = \dfrac{1}{2}m(3v)^2 = \dfrac{1}{2}m \times 9v^2 = 9 \times \dfrac{1}{2}mv^2\).
So \(\dfrac{KE'}{KE} = 3^2 = 9\). Hence the kinetic energy becomes 9 times its original value.