Walking at \(\dfrac{3}{5}\) of his normal speed from his home, Vishal is 24 minutes late in reaching his office. The usual time he takes to cover the distance between his home and his office is:
36 minutes
For a fixed distance, time is inversely proportional to speed.
Walking at \(\dfrac{3}{5}\) of the normal speed makes the time \(\dfrac{5}{3}\) of the usual time.
Let the usual time be \(t\). The extra time taken \(= \dfrac{5}{3}t - t = \dfrac{2}{3}t\).
This extra time is the delay, so \(\dfrac{2}{3}t = 24\).
\(t = 24 \times \dfrac{3}{2} = 36\) minutes.
Hence, the usual time is 36 minutes.
Similar Questions
Walking at \(\dfrac{3}{4}\) of his normal speed from his home, Tarun is 19 minutes late to his office. The usual time taken by him to cover the distance between his home and his office is:
Important Questions from Speed Time and Distance
A journey of 900 km is completed in 11 h. If two-fifth of the journey is completed at the speed of 60 km/h, at what speed (in km/h) is the remaining journey completed?
A car starts from point A towards point B, travelling at the speed of 20 km/h. 1 \(\frac{1}{2}\) hours later, another car starts from point A and travelling at the speed of 30 km/h and reaches 2 \(\frac{1}{2}\) hours before the first car. Find the distance between A and B.
A bus covered a distance of 162 km. If speed of this bus is 15 m/s, then what will be the time taken ?
An athlete runs an 800 m race in 96 seconds. His speed (in km / h) is:
A person has to cover a distance of 150 km in 15 hours. If he traveled with the speed of 11.8 km/hr for 10 hours. At what speed he has to travel to cover the remaining distance in the remaining time?
