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Question

Two trains start at the same time from stations P and Q and travel towards each other at the speeds of 75 km/h and 100 km/h, respectively. When they meet, it is found that one train has travelled 50 km more than the other. The distance (in km) between two stations is:

This question was previously asked in
SSC Selection Post 2024 Question Paper (26-Jun-2024) (Shift-4)
The correct answer is
350

Understanding the Train Meeting Problem

This problem involves two trains starting at the same time from different stations and traveling towards each other. We are given their speeds and the difference in the distance they cover when they meet. Our goal is to find the total distance between the two stations.

Given Information:

  • Speed of the first train (from station P): $S_P = 75$ km/h
  • Speed of the second train (from station Q): $S_Q = 100$ km/h
  • Difference in distance traveled when they meet: 50 km
  • The trains start at the same time.

Step-by-Step Solution

Let's break down the problem to find the solution.

  1. Define Time and Distance Variables:

    Let the time (in hours) taken for the two trains to meet be $t$. Since they start at the same time, they travel for the same duration until they meet.

    The distance traveled by the first train (from P) is $D_P$.

    The distance traveled by the second train (from Q) is $D_Q$.

  2. Express Distances in Terms of Time:

    Using the formula distance = speed × time:

    • Distance traveled by the first train: $D_P = S_P \times t = 75t$ km
    • Distance traveled by the second train: $D_Q = S_Q \times t = 100t$ km
  3. Use the Distance Difference Condition:

    We are told that when they meet, one train has traveled 50 km more than the other. Since the second train is faster (100 km/h vs 75 km/h), it will cover more distance.

    Therefore, the difference in distance is: $D_Q - D_P = 50$ km

  4. Solve for Time ($t$):

    Substitute the expressions for $D_Q$ and $D_P$ into the difference equation:

    $100t - 75t = 50$

    Simplify the equation:

    $25t = 50$

    Solve for $t$:

    $t = \frac{50}{25} = 2$ hours

    So, the trains meet after 2 hours.

  5. Calculate the Total Distance:

    The total distance between stations P and Q is the sum of the distances traveled by both trains until they meet.

    Total Distance = $D_P + D_Q$

    We can calculate this in two ways:

    • Method 1: Calculate individual distances and add them.
      • $D_P = 75 \times t = 75 \times 2 = 150$ km
      • $D_Q = 100 \times t = 100 \times 2 = 200$ km
      • Total Distance = $150 + 200 = 350$ km
    • Method 2: Use the combined speed. The relative speed of the trains approaching each other is $S_P + S_Q = 75 + 100 = 175$ km/h. The total distance covered is this relative speed multiplied by the time taken to meet.
      • Total Distance = $(S_P + S_Q) \times t = (75 + 100) \times 2 = 175 \times 2 = 350$ km

    Both methods confirm the total distance.

Final Answer

The distance between the two stations P and Q is 350 km.

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Important Questions from Speed Time and Distance

  1. A train travelling at a speed of 72 km/hr crosses a post in 20 seconds. If it crosses another train travelling at a speed of 54 km/hr in the same direction in 1 minute 45 seconds, then the difference in length between the two trains is

  2. Rajiv's boat can travel along the current at the 8 km/hour and against the current at the rate 6 km/hour. Find the time taken by the boat to sail 28 km in still water.

  3. Two trains running in opposite directions cross a man standing on the platform in 25 seconds and 32 seconds respectively and they cross each other in 30 seconds. The ratio of their speed is:

  4. A worker covers a distance of 81 km in 11 hours. He travels partly on foot at 4.5 km/h and partly on bicycle at 15 km/h. What is the distance covered on the cycle?

  5. A car travels from a place X to place Y at an average speed of v km/hr from y to X at an average speed of 2v km/hr, again from X to y at an average speed of 3v km/hr and again from y to x at an average speed of 4v km/hr. Then the average speed of the car for the entire journey

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