When two harmonic waves moving in the same direction superimpose, and their frequencies are close, the resultant wave exhibits a phenomenon called beating. This means the amplitude of the resultant wave varies periodically over time.
The given wave equation is $x = a \cos (1.5t) \cos (50.5t)$. This equation is a product of two cosine terms. To understand the superposition of two underlying harmonic waves, we use the trigonometric identity:
$ \cos A \cos B = \frac{1}{2} [\cos(A-B) + \cos(A+B)] $
Let $A = 50.5t$ and $B = 1.5t$. Applying the identity to the given equation:
$ x = \frac{a}{2} [\cos((50.5 - 1.5)t) + \cos((50.5 + 1.5)t)] $
$ x = \frac{a}{2} [\cos(49t) + \cos(52t)] $
This resulting form shows the superposition of two harmonic waves with angular frequencies $\omega_1 = 49 \text{ rad/s}$ and $\omega_2 = 52 \text{ rad/s}$.
The difference between the angular frequencies of the two component waves determines the beating phenomenon. The difference is:
$ |\omega_2 - \omega_1| = |52 \text{ rad/s} - 49 \text{ rad/s}| = 3 \text{ rad/s} $
The beat frequency ($f_{beat}$) is half the difference between the angular frequencies, divided by $\pi$:
$ f_{beat} = \frac{|\omega_2 - \omega_1|}{2\pi} = \frac{3}{2\pi} \text{ Hz} $
The period of beating ($T_{beat}$) is the time it takes for one complete cycle of the amplitude variation. It is the reciprocal of the beat frequency:
$ T_{beat} = \frac{1}{f_{beat}} = \frac{2\pi}{|\omega_2 - \omega_1|} $
Substituting the calculated frequency difference:
$ T_{beat} = \frac{2\pi}{3} \text{ s} $
To find the value closest to an integer, we calculate the numerical value of $T_{beat}$:
$ T_{beat} \approx \frac{2 \times 3.14159}{3} \approx 2.094 \text{ s} $
Comparing this value to the given options, $2.094 \text{ s}$ is closest to $2 \text{ s}$.
Two simple harmonic motions, as shown below, are at right angles. They are combined to form lissajous figures.
$x(t) = A \sin (at + \delta)$
$y(t) = B \sin (bt)$
Identify the correct match below :
The motion of a mass on a spring, with spring constant K is as shown in figure.
The equation of motion is given by $x(t) = A\sin\omega t+B\cos\omega t$ with $\omega=\sqrt{\frac{K}{m}}$.
Suppose that at time $t = 0$, the position of mass is $x(0)$ and velocity $v(0)$, then its displacement can also be represented as $x(t) = C\cos(\omega t-\phi)$, where $C$ and $\phi$ are

A piston of mass $M$ is hung from a massless spring whose restoring force law goes as $F= -kx^3$, where $k$ is the spring constant of appropriate dimension. The piston separates the vertical chamber into two parts, where the bottom part is filled with 'n' moles of an ideal gas. An external work is done on the gas isothermally (at a constant temperature $T$) with the help of a heating filament (with negligible volume) mounted in lower part of the chamber, so that the piston goes up from a height $L_0$ to $L_1$, the total energy delivered by the filament is : (Assume spring to be in its natural length before heating)