Three students $S_1$, $S_2$ and $S_3$ perform an experiment for determining the acceleration due to gravity (g) using a simple pendulum. They use different lengths of pendulum and record time for different number of oscillations. The observations are as shown in the table. (least count of length =0.1 cm least count for time =0.1s ) If $E_1$, $E_2$ and $E_3$ are the percentage errors in 'g' for students 1, 2 and 3 respectively, then the minimum percentage error is obtained by student no. __________.
The formula for the acceleration due to gravity (g) using a simple pendulum is given by:
\( g = \frac{4\pi^2L}{T^2} \)
where \( L \) is the length of the pendulum and \( T \) is the time period for one oscillation.
The percentage error in g, \( E \), can be calculated by the formula:
\( E = \left(\frac{\Delta L}{L} + 2\frac{\Delta T}{T}\right) \times 100\% \)
where \( \Delta L \) and \( \Delta T \) are the least counts for L and T respectively.
Comparing \( E_1, E_2, \) and \( E_3 \), we find that the minimum percentage error is for Students 1 and 2, both at \( 1\% \).
Therefore, the minimum percentage error is obtained by student no. 1
| List - I | List - II |
| A. Meter (L) | I. $\sqrt{\frac{hc}{G}}$ |
| B. Second (S) | II. $\sqrt{\frac{Gh}{c^{5}}}$ |
| C. Kilogram (M) | III. $\sqrt{\frac{K^{2}L^{2}c^{3}}{Gh}}$ |
| D. Kelvin (K) | IV. $\sqrt{\frac{Gh}{c^{3}}}$ |
A man in a car at location Q on a straight highway is moving with speed v. He decides to reach a point P in qa field at a distance d from the highway (point m) as shown in the figure. Speed of the car in the field is half to that on the highway. What should be the distance RM, so that the time taken to reach P is minimum ?

| List - I | List - II |
| A. Meter (L) | I. $\sqrt{\frac{hc}{G}}$ |
| B. Second (S) | II. $\sqrt{\frac{Gh}{c^{5}}}$ |
| C. Kilogram (M) | III. $\sqrt{\frac{K^{2}L^{2}c^{3}}{Gh}}$ |
| D. Kelvin (K) | IV. $\sqrt{\frac{Gh}{c^{3}}}$ |