Three resistors, 9Ω, 9 Ω and X Ω, are connected in parallel. Total resistance of this parallel combination is 3 Ω. Find the unknown resistance X Ω.
9 Ω
When resistors are connected in parallel, the current divides among them, and the voltage across each resistor is the same. The total resistance of a parallel combination is always less than the smallest individual resistance.
The formula for calculating the total resistance (\(\small R_{total}\)) of resistors connected in parallel is given by the reciprocal of the sum of the reciprocals of individual resistances:
\(\small \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + ...\)
In this specific problem, we are given three resistors connected in parallel with resistances \(\small R_1 = 9 \, \Omega\), \(\small R_2 = 9 \, \Omega\), and \(\small R_3 = X \, \Omega\). The total resistance of this parallel combination is \(\small R_{total} = 3 \, \Omega\). We need to find the value of the unknown resistance \(\small X\).
We can use the formula for the total resistance of resistors in parallel:
\(\small \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}\)
Substitute the given values into the formula:
\(\small \frac{1}{3} = \frac{1}{9} + \frac{1}{9} + \frac{1}{X}\)
Combine the terms with known values:
\(\small \frac{1}{3} = \frac{2}{9} + \frac{1}{X}\)
To find \(\small \frac{1}{X}\), rearrange the equation:
\(\small \frac{1}{X} = \frac{1}{3} - \frac{2}{9}\)
To subtract the fractions on the right side, find a common denominator, which is 9:
\(\small \frac{1}{3} = \frac{1 \times 3}{3 \times 3} = \frac{3}{9}\)
So the equation becomes:
\(\small \frac{1}{X} = \frac{3}{9} - \frac{2}{9}\)
Subtract the fractions:
\(\small \frac{1}{X} = \frac{3 - 2}{9}\)
\(\small \frac{1}{X} = \frac{1}{9}\)
To find \(\small X\), take the reciprocal of both sides:
\(\small X = 9 \, \Omega\)
Let's check if the calculated value of \(\small X = 9 \, \Omega\) gives the correct total resistance when combined in parallel with two other \(\small 9 \, \Omega\) resistors:
\(\small \frac{1}{R_{total}} = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\)
\(\small \frac{1}{R_{total}} = \frac{1+1+1}{9}\)
\(\small \frac{1}{R_{total}} = \frac{3}{9}\)
\(\small \frac{1}{R_{total}} = \frac{1}{3}\)
Taking the reciprocal:
\(\small R_{total} = 3 \, \Omega\)
This matches the total resistance given in the problem, confirming our calculation is correct.
The unknown resistance \(\small X\) in the parallel combination is \(\small 9 \, \Omega\). This means all three resistors in the parallel circuit have the same resistance value.
| Concept | Description | Formula (for n resistors) |
|---|---|---|
| Voltage (V) | Same across all resistors | \(\small V_{total} = V_1 = V_2 = ... = V_n\) |
| Current (I) | Total current is the sum of currents through each resistor | \(\small I_{total} = I_1 + I_2 + ... + I_n\) |
| Total Resistance (\(\small R_{total}\)) | Reciprocal of the sum of reciprocals | \(\small \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n}\) |
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