Three resisters of 3 ohm, 10 ohm and 15 ohm are connected in parallel in a 30 V circuit. The current will that flow through the 3-ohm resistor is:
10 A
When resistors are connected in parallel in a circuit, the voltage across each resistor is the same and is equal to the total voltage supplied by the source. In this problem, three resistors with resistances of 3 ohm, 10 ohm, and 15 ohm are connected in parallel to a 30 V circuit.
We need to find the current that flows specifically through the 3-ohm resistor. To do this, we can use Ohm's Law, which relates voltage (V), current (I), and resistance (R).
Ohm's Law is given by the formula:
\(V = IR\)
Where:
To find the current (\(I\)) flowing through a specific resistor, we can rearrange the formula to:
\(I = \frac{V}{R}\)
Since the resistors are in parallel, the voltage across the 3-ohm resistor is the same as the total circuit voltage, which is 30 V.
We have:
Using Ohm's Law (\(I = \frac{V}{R}\)), we can calculate the current flowing through the 3-ohm resistor:
\(I_{3\Omega} = \frac{V}{R_{3\Omega}}\)
\(I_{3\Omega} = \frac{30 \, V}{3 \, \Omega}\)
\(I_{3\Omega} = 10 \, A\)
Therefore, the current that will flow through the 3-ohm resistor is 10 A.
| Resistor Resistance | Voltage Across Resistor | Current Through Resistor (Calculated) |
|---|---|---|
| 3 ohm | 30 V | 10 A |
| 10 ohm | 30 V | \(I_{10\Omega} = \frac{30 V}{10 \Omega} = 3 A\) |
| 15 ohm | 30 V | \(I_{15\Omega} = \frac{30 V}{15 \Omega} = 2 A\) |
The total current drawn from the source would be the sum of the currents through each parallel branch: \(10 A + 3 A + 2 A = 15 A\).
The current flowing specifically through the 3-ohm resistor is 10 A.
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