Initially, there are 100 students in the hostel.
The food provisions are sufficient for these 100 students for 20 days.
An additional 25 students join the hostel.
The new total number of students is calculated as:
$ \text{Total Students} = 100 + 25 = 125 \text{ students} $
This problem involves inverse proportion. If the number of students increases, the number of days the provisions last decreases proportionally.
Let $S_1$ be the initial number of students and $D_1$ be the initial number of days the provisions last.
Let $S_2$ be the final number of students and $D_2$ be the final number of days the provisions last.
The relationship is: $ S_1 \times D_1 = S_2 \times D_2 $
Substitute the known values into the equation:
$ 100 \text{ students} \times 20 \text{ days} = 125 \text{ students} \times D_2 $
Now, solve for $D_2$:
$ D_2 = \frac{100 \times 20}{125} $
$ D_2 = \frac{2000}{125} $
$ D_2 = 16 \text{ days} $
Therefore, the same food provisions will last for 16 days if 25 more students join the hostel.
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