To determine the relationship between the volume of a sphere and a cube, we calculate their volumes based on the given dimensions.
The sphere has a diameter of 1 unit.
The cube has a side length of 1 unit.
Compare the calculated volumes:
Since $0.5236 < 1$, the volume of the sphere is less than the volume of the cube.
The correct comparative term is 'less'. The volume of the sphere (diameter 1 unit) is less than the volume of the cube (side 1 unit).
In the given figure, PQRS is a square of side 2 cm and PLMN is a rectangle. The corner L of the rectangle is on the side QR. Side MN of the rectangle passes through the corner S of the square.
What is the area (in cm²) of the rectangle PLMN?
Note: The figure shown is representative.

A regular dodecagon (12-sided regular polygon) is inscribed in a circle of radius $r$ cm as shown in the figure. The side of the dodecagon is $d$ cm. All the triangles (numbered 1 to 12) in the figure are used to form squares of side $r$ cm and each numbered triangle is used only once to form a square.
The number of squares that can be formed and the number of triangles required to form each square, respectively, are:
Note: The figure shown is representative.