The problem requires finding the area of a window composed of a square and an equilateral triangle.
Let 's' represent the side length of the square. Since the equilateral triangle sits atop the square, sharing a side, the triangle's side length is also 's'.
The window's perimeter comprises the bottom edge of the square and the two vertical sides of the square, plus the two exposed vertical sides of the triangle.
Wait, let's reconsider the perimeter. The perimeter is the outer boundary. This includes:
Therefore, the total perimeter is the sum of these 5 sides:
Perimeter = s + s + s + s + s = 5s.
We are given that the perimeter is 6 m:
$5s = 6 \text{ m}$
Solving for the side length 's':
$s = \frac{6}{5} \text{ m} = 1.2 \text{ m}$
The total area of the window is the sum of the area of the square portion and the area of the equilateral triangle portion.
The formula for the area of a square is $A_{square} = s^2$.
Using $s = 1.2$ m:
$A_{square} = (1.2 \text{ m})^2 = 1.44 \text{ m}^2$
The formula for the area of an equilateral triangle is $A_{triangle} = \frac{\sqrt{3}}{4} s^2$.
Using $s = 1.2$ m:
$A_{triangle} = \frac{\sqrt{3}}{4} (1.2 \text{ m})^2 = \frac{\sqrt{3}}{4} \times 1.44 \text{ m}^2$
$A_{triangle} = \sqrt{3} \times 0.36 \text{ m}^2$
Using the approximation $\sqrt{3} \approx 1.732$:
$A_{triangle} \approx 1.732 \times 0.36 \text{ m}^2 \approx 0.6235 \text{ m}^2$
Sum the areas of the square and the triangle:
$A_{total} = A_{square} + A_{triangle}$
$A_{total} \approx 1.44 \text{ m}^2 + 0.6235 \text{ m}^2$
$A_{total} \approx 2.0635 \text{ m}^2$
Rounding to two decimal places gives the final area.
The area of the window is approximately 2.06 $m^2$.
In the given figure, PQRS is a square of side 2 cm and PLMN is a rectangle. The corner L of the rectangle is on the side QR. Side MN of the rectangle passes through the corner S of the square.
What is the area (in cm²) of the rectangle PLMN?
Note: The figure shown is representative.

A regular dodecagon (12-sided regular polygon) is inscribed in a circle of radius $r$ cm as shown in the figure. The side of the dodecagon is $d$ cm. All the triangles (numbered 1 to 12) in the figure are used to form squares of side $r$ cm and each numbered triangle is used only once to form a square.
The number of squares that can be formed and the number of triangles required to form each square, respectively, are:
Note: The figure shown is representative.