The volume of a sealed packet is 1 liter and its mass is 800 g. The packet is first put inside the water with a density of 1 g cm -3 and then in another liquid B with a density of 1.5 g cm -3 . Then which one of the following statements holds true?
The packet will float in both water and liquid B.
Whether an object floats or sinks in a liquid depends on the comparison between the density of the object and the density of the liquid. If the object's density is less than the liquid's density, the object will float. If the object's density is greater than the liquid's density, the object will sink. If the densities are equal, the object will remain suspended within the liquid.
We are given the volume and mass of the sealed packet. We can calculate its density using the formula:
\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]
The given values are:
First, we need to convert the volume from liters to cubic centimeters (cm³) to match the units of the liquid densities (g/cm³). We know that 1 liter is equal to 1000 cubic centimeters.
\[ \text{Volume} = 1 \text{ liter} = 1000 \text{ cm}^3 \]
Now, we can calculate the density of the packet:
\[ \text{Density of packet} = \frac{800 \text{ g}}{1000 \text{ cm}^3} = 0.8 \text{ g/cm}^3 \]
So, the density of the sealed packet is 0.8 g/cm³.
Now we compare the density of the packet with the densities of water and liquid B.
The density of the packet is 0.8 g/cm³.
The density of water is given as 1 g/cm³.
Comparing the densities:
\[ \text{Density of packet} \, (0.8 \text{ g/cm}^3) \, \text{ vs. } \, \text{Density of water} \, (1 \text{ g/cm}^3) \]
Since 0.8 g/cm³ < 1 g/cm³, the density of the packet is less than the density of water. Therefore, the packet will float in water.
The density of liquid B is given as 1.5 g/cm³.
Comparing the densities:
\[ \text{Density of packet} \, (0.8 \text{ g/cm}^3) \, \text{ vs. } \, \text{Density of liquid B} \, (1.5 \text{ g/cm}^3) \]
Since 0.8 g/cm³ < 1.5 g/cm³, the density of the packet is less than the density of liquid B. Therefore, the packet will float in liquid B.
Based on the density calculations and comparisons:
Thus, the packet will float in both water and liquid B.
| Property | Value/Liquid | Result/Comparison |
|---|---|---|
| Packet Mass | 800 g | Given |
| Packet Volume | 1 liter (1000 cm³) | Given & Conversion |
| Packet Density | 0.8 g/cm³ | Calculated (800 g / 1000 cm³) |
| Water Density | 1 g/cm³ | Given |
| Liquid B Density | 1.5 g/cm³ | Given |
| Packet vs. Water | 0.8 g/cm³ < 1 g/cm³ | Packet floats in water |
| Packet vs. Liquid B | 0.8 g/cm³ < 1.5 g/cm³ | Packet floats in liquid B |
The concept of floating and sinking is explained by Archimedes' Principle. This principle states that a body immersed in a fluid experiences an upward buoyant force equal to the weight of the fluid displaced by the body. The buoyant force acts opposite to gravity.
Relating this to density: The weight of the object is \( \text{Volume}_{\text{object}} \times \text{Density}_{\text{object}} \times g \). The buoyant force is the weight of the displaced fluid, which is \( \text{Volume}_{\text{submerged}} \times \text{Density}_{\text{fluid}} \times g \).
For a fully submerged object with Volume \(V\):
Our density comparison method is a direct application of Archimedes' Principle.
Buoyancy is a/an
A metallic sphere with an internal cavity weight 40g in air and in water it weighs 20g. If the density of material with cavity be 8 gm/cc then the volume of cavity is:
A piece of copper of density 8.8 g/cm 3 having an internal cavity weight 264 g in air and 221 g in water. the volume of cavity is: