The transcription factor X binds a 10 base pair DNA stretch. In the DNA of an organism, X was found to bind at 20 distinct sites. An analysis of these 20 binding sites showed the following distribution: What is the consensus sequence for the binding site of X?Base Position in the binding site 1 2 3 4 5 6 7 8 9 10 A 11 0 0 0 16 2 4 0 4 3 T 3 0 19 0 1 3 4 20 2 4 G 4 20 0 0 2 4 6 0 12 2 C 2 0 1 20 1 11 6 0 2 11
AGTCACNTGC
The consensus sequence represents the most frequent nucleotide found at each position across a set of related DNA sequences, such as transcription factor binding sites. It is determined by analyzing the distribution of bases (A, T, G, C) at each site position.
The following table shows the counts of each base at 10 positions within 20 binding sites for transcription factor X:
| Base | Pos 1 | Pos 2 | Pos 3 | Pos 4 | Pos 5 | Pos 6 | Pos 7 | Pos 8 | Pos 9 | Pos 10 |
|---|---|---|---|---|---|---|---|---|---|---|
| A | 11 | 0 | 0 | 0 | 16 | 2 | 4 | 0 | 43 | 3 |
| T | 3 | 0 | 19 | 13 | 4 | 2 | 0 | 20 | 24 | 24 |
| G | 4 | 19 | 0 | 0 | 24 | 6 | 0 | 1 | 22 | 2 |
| C | 2 | 12 | 12 | 20 | 1 | 11 | 16 | 2 | 1 | 11 |
The most frequent base at each position is identified:
This analysis yields a consensus sequence of AGTCGCCTAT. The question provides Option B (AGTCACNTGC) as the correct answer.
The contour length of a B-DNA molecule that encodes a bacterial protein of 33 kDa is _________ nm.
Consider the average molecular weight of an amino acid as 110 Da and helix rise per base pair for B-DNA as 0.34 nm.
(Round off to the nearest integer)