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Question

The temperature of a body increases from \(310\) K to \(340\) K. The temperature increase in degree Celsius is

This question was previously asked in
NDA 2 2025 GAT Question Paper (14-Sep-2025)
The correct answer is
\(30^\circ\)C

Temperature Conversion Explained

The question asks us to find the increase in temperature in degrees Celsius (\(^\circ\)C) when the temperature of a body rises from an initial temperature (\(T_1\)) of \(310\) K to a final temperature (\(T_2\)) of \(340\) K.

Understanding Temperature Scales

Temperature can be measured in different scales, such as Kelvin (K) and Celsius (\(^\circ\)C). The Kelvin scale is an absolute temperature scale, while the Celsius scale is relative to the freezing point of water.

  • The relationship between Kelvin and Celsius is given by: \(T(^\circ\text{C}) = T(\text{K}) - 273.15\)
  • However, when calculating the temperature difference (increase or decrease), the conversion factor cancels out. This is because a change of 1 Kelvin is equal in magnitude to a change of 1 degree Celsius. \( \Delta T(\text{K}) = T_2(\text{K}) - T_1(\text{K}) \) \( \Delta T(^\circ\text{C}) = T_2(^\circ\text{C}) - T_1(^\circ\text{C}) \) Substituting the conversion formula: \( \Delta T(^\circ\text{C}) = (T_2(\text{K}) - 273.15) - (T_1(\text{K}) - 273.15) \) \( \Delta T(^\circ\text{C}) = T_2(\text{K}) - 273.15 - T_1(\text{K}) + 273.15 \) \( \Delta T(^\circ\text{C}) = T_2(\text{K}) - T_1(\text{K}) \) \( \Delta T(^\circ\text{C}) = \Delta T(\text{K}) \)

Calculating the Temperature Increase

We need to find the change in temperature, \(\Delta T\). We can calculate this difference directly in Kelvin first.

  • Given:
    • Initial Temperature, \(T_1 = 310\) K
    • Final Temperature, \(T_2 = 340\) K
  • Step 1: Calculate the temperature difference in Kelvin. \( \Delta T(\text{K}) = T_2 - T_1 \) \( \Delta T(\text{K}) = 340 \text{ K} - 310 \text{ K} \) \( \Delta T(\text{K}) = 30 \text{ K} \)
  • Step 2: Convert the temperature difference to Celsius. As established earlier, the temperature difference in Kelvin is numerically equal to the temperature difference in Celsius. \( \Delta T(^\circ\text{C}) = \Delta T(\text{K}) \) \( \Delta T(^\circ\text{C}) = 30 \text{ K} \) Therefore, the temperature increase is \(30^\circ\)C.

Final Answer

The temperature increase from \(310\) K to \(340\) K is \(30^\circ\)C.

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