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Question

The sum of the age of A and 5 times the age of B is 55 years. When 3 times the age of A is added to 7 times the age of B, the result is 99 years. The sum of the ages (in years) of A and B is:

The correct answer is
22

This problem involves setting up and solving a system of linear equations based on the information given about the ages of two people, A and B.

Age Word Problem Setup

First, let's define variables for the unknown ages:

  • Let $A$ be the current age of person A.
  • Let $B$ be the current age of person B.

Now, we translate the sentences from the question into mathematical equations:

  1. "The sum of the age of A and 5 times the age of B is 55 years." This translates to:

    $ A + 5B = 55 \quad (Equation \, 1) $

  2. "When 3 times the age of A is added to 7 times the age of B, the result is 99 years." This translates to:

    $ 3A + 7B = 99 \quad (Equation \, 2) $

Our goal is to find the sum of their ages, which is $A + B$. To do this, we first need to find the individual values of $A$ and $B$ by solving the system of equations.

Solving the System of Linear Equations

We can use the elimination method to solve the system:

$ A + 5B = 55 \quad (1) $

$ 3A + 7B = 99 \quad (2) $

To eliminate $A$, we can multiply Equation 1 by 3:

$ 3 \times (A + 5B) = 3 \times 55 $

$ 3A + 15B = 165 \quad (Equation \, 3) $

Now, subtract Equation 2 from Equation 3:

$ (3A + 15B) - (3A + 7B) = 165 - 99 $

$ 3A + 15B - 3A - 7B = 66 $

$ 8B = 66 $

Solve for $B$:

$ B = \frac{66}{8} $

Simplify the fraction:

$ B = \frac{33}{4} $

Now, substitute the value of $B$ back into Equation 1 to find $A$:

$ A + 5B = 55 $

$ A + 5 \left( \frac{33}{4} \right) = 55 $

$ A + \frac{165}{4} = 55 $

Solve for $A$:

$ A = 55 - \frac{165}{4} $

To subtract, find a common denominator:

$ A = \frac{55 \times 4}{4} - \frac{165}{4} $

$ A = \frac{220}{4} - \frac{165}{4} $

$ A = \frac{220 - 165}{4} $

$ A = \frac{55}{4} $

Calculating the Sum of Ages

We have found the ages:

  • $A = \frac{55}{4}$ years
  • $B = \frac{33}{4}$ years

The question asks for the sum of the ages, $A + B$.

$ A + B = \frac{55}{4} + \frac{33}{4} $

Since the denominators are the same, we can add the numerators:

$ A + B = \frac{55 + 33}{4} $

$ A + B = \frac{88}{4} $

$ A + B = 22 $

So, the sum of the ages of A and B is 22 years.

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Important Questions from Problem on Ages (Notes)

  1. The sum of the age of A and 3 times the age of B is 43 years. When 5 times the age of A is added to 2 times the age of B, the result is 98 years. The sum of the ages (in years) of A and B is:
  2. Eight years ago, the age of the mother was four times the age of her son. Eight years hence, the mother's age will be two times the age of her son. Find the ratio of the present age of the mother to the age of the son.
  3. The sum of the age of A and 5 times the age of B is 36 years. When 3 times the age of A is added to 7 times the age of B, the result is 62 years. The sum of the ages (in years) of A and B is:
  4. The difference between the squares of the ages (in complete years) of a father and his son is 899. The age of the father when his son was born

  5. The average age of $A, B$ and $C$, whose ages are integers $x, y$ and $z$ respectively ($x \le y \le z$), is 30. If the age of $B$ is exactly 5 more than that of $A$, what is the minimum possible value of $z$?
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