This problem involves setting up and solving a system of linear equations based on the information given about the ages of two people, A and B.
First, let's define variables for the unknown ages:
Now, we translate the sentences from the question into mathematical equations:
$ A + 5B = 55 \quad (Equation \, 1) $
$ 3A + 7B = 99 \quad (Equation \, 2) $
Our goal is to find the sum of their ages, which is $A + B$. To do this, we first need to find the individual values of $A$ and $B$ by solving the system of equations.
We can use the elimination method to solve the system:
$ A + 5B = 55 \quad (1) $
$ 3A + 7B = 99 \quad (2) $
To eliminate $A$, we can multiply Equation 1 by 3:
$ 3 \times (A + 5B) = 3 \times 55 $
$ 3A + 15B = 165 \quad (Equation \, 3) $
Now, subtract Equation 2 from Equation 3:
$ (3A + 15B) - (3A + 7B) = 165 - 99 $
$ 3A + 15B - 3A - 7B = 66 $
$ 8B = 66 $
Solve for $B$:
$ B = \frac{66}{8} $
Simplify the fraction:
$ B = \frac{33}{4} $
Now, substitute the value of $B$ back into Equation 1 to find $A$:
$ A + 5B = 55 $
$ A + 5 \left( \frac{33}{4} \right) = 55 $
$ A + \frac{165}{4} = 55 $
Solve for $A$:
$ A = 55 - \frac{165}{4} $
To subtract, find a common denominator:
$ A = \frac{55 \times 4}{4} - \frac{165}{4} $
$ A = \frac{220}{4} - \frac{165}{4} $
$ A = \frac{220 - 165}{4} $
$ A = \frac{55}{4} $
We have found the ages:
The question asks for the sum of the ages, $A + B$.
$ A + B = \frac{55}{4} + \frac{33}{4} $
Since the denominators are the same, we can add the numerators:
$ A + B = \frac{55 + 33}{4} $
$ A + B = \frac{88}{4} $
$ A + B = 22 $
So, the sum of the ages of A and B is 22 years.
A father said to his son, "I was as old as you are when I became your father." If the current age of father is 52 years, the age of son after 10 years will be___________.